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GPL-2.0

This project bases on the Extension project of DETA Socket PLSQL DB.

20210320 Initon Math Yaoguang Luo

20210320 元基数学 罗瑶光

自从有了AOPM VECS IDUQ TXH DD ,16个元基成分,我今天定义为16进制的数字,对应为

既然是严谨定义, 自然要用生化和语义双元基罗盘来进行推导开始。

我先设未知的为X
A XXXX
O XXXX
P XXXX
M XXXX
V XXXX
E XXXX
C XXXX
S XXXX
I XXX1
D XXX0
U XXX2
Q XXX3
T XXXX
X XXXX
HE XXXX
HC XXXX
DD 补码

根据第一卷 和 第二卷283和284页,我能列出来的 新增 关系式 E -> HE, C -> HC.

根据 数字逻辑 和 离散数学 位列比 和 寄存法则 推导 VECS 为 :

A XXXX
O XXXX
P XXXX
M XXXX
V XXX1
E XXX2
C XXX0
S XXX3
I 0001
D 0000
U 0002
Q 0003
T XXXX
X XXXX
HE XXX2
HC XXX0
DD 补码

准备写个欧拉路径算法开始计算 。 第一卷的 数据预测 包 此时派上了用场。

方便大家理解。

刚计算了欧拉元基环路 QUIVT+OSMAX-HEPCD 我定义17进制的数据为

QUIVT+OSMAX-HEPCD DD
GFEDCBA9876543210 CARRY

我在思考怎么缩进成16进制。 先保证逻辑的严谨性, 我先用17进制走一段路程。

17进制数据已经问世,我今天深入下,进行元基础加法 探索,wechat已经发布了,在这里整理如下;

元基础数字 = 元基符号 = 生化名称
0 = D = 胞嘧啶
1 = C = 鸟嘌呤
2 = P = 尿胞变鸟苷
3 = E = 尿变嘌呤
4 = H = 黄嘌呤
5 = - =
6 = X = 变感腺鸟苷
7 = A = 变感腺腺苷
8 = M = 鸟腺苷
9 = S = 腺嘌呤
A = O = 尿胞变腺苷
B = + =
C = T = 变感腺尿变苷
D = V = 变感腺嘌呤
E = I = 尿嘧啶
F = U = 变嘧啶
G = Q = 胸腺嘧啶

数字逻辑的推导(C=U+D+D)

语义肽展公式推导

元基数字 =元基符号 = 肽展公式数字变换
0 = D = 0 + 0
1 = C = 0 + F
2 = P = 3 + 1
3 = E = F + 0
4 = H = 3 OR 1
5 = - =
6 = X = D + -
7 = A = D + 9
8 = M = - + 9
9 = S = G + E
A = O = 3 + 9
B = + =
C = T = D + 3
D = V = F + G
E = I =
F = U =
G = Q =

元基数学加法表 根据 4 的归纳完整推导如下

元基数字 = 元基符号= 肽展公式数字变换

0 = D = 0 + 0

1 = C = 0 + F

2 = P = 3 + 1

3 = E = F + 0

4 = H = 3 OR 1

5 = - = 4 + 1

6 = X = D + 5

7 = A = D + 9

8 = M = 5 + 9

9 = S = G + E

A = O = 3 + 9

B = + = 4 + 3

C = T = D + B

D = V = F + G

E = I = E

F = U = E++ OR G--

G = Q = G

20210322 今早把十七进制的元基组合数学变换 定义了,归纳整理如下:

我的思路是 元基稳定化DEFG变换

元基数字 = 元基符号= 肽展公式元基变换

0 = D = 00
1 = C = 02
2 = P = 2002
3 = E = 20
4 = H = 20, 02
5 = - = 2002, 0202
6 = X = 23(2002, 0202)
7 = A = 2331
8 = M = (2002, 0202)31
9 = S = 31
A = O = 2031
B = + = 2020, 0220
C = T = 23(2020, 0220)
D = V = 23
E = I = 1
F = U = 2
G = Q = 3

稳定化后于是元基替换为 0123-> DIUQ 如下

0 = D = D + D
1 = C = DU
2 = P = UDDU
3 = E = UD
4 = H = UD, DU
5 = - = (UD, DU)DU
6 = X = UQ(UD, DU)DU
7 = A = UQQI
8 = M = (UD, DU)DUQI
9 = S = QI
A = O = UDQI
B = + = (UD, DU)UD
C = T = UQ(UD, DU)UD
D = V = UQ
E = I = I
F = U = U
G = Q = Q

我在思考 这个括号内的元基如果进行之后计算的唯一化。 到现在 十进制常数进行元基码 变换的思路已经问世了,下一步,养疗经真实应用。 这里的 568B 我推测又是一组概率钥匙酸碱控制。我也会真实应用测试论证。

今天多做一点推导:我把0到G的欧拉顺序 改成 线性数学顺序观测如下:

0 = D = D + D
E = I = I
F = U = U
G = Q = Q
1 = C = DU
D = V = UQ
3 = E = UD
9 = S = QI
7 = A = UQQI
2 = P = UDDU
A = O = UDQI
4 = H = UD, DU
5 = - = (UD, DU)DU
B = + = (UD, DU)UD
6 = X = UQ(UD, DU)DU
C = T = UQ(UD, DU)UD
8 = M = (UD, DU)DUQI

我想这个顺序别有用途,先搁置。

下一步 H 化简HE+, HC- , 然后重新线性排列如下

0 = D = D
E = I = I
F = U = U
G = Q = Q
1 = C = DU
3 = E = UD
4 = H = UD, DU
D = V = UQ
9 = S = QI
5 = - = DUDU
2 = P = UDDU
B = + = UDUD
A = O = UDQI
7 = A = UQQI
8 = M = DUDUQI
6 = X = UQDUDU
C = T = UQUDUD

修正后如下

0 = D = D
E = I = I
F = U = U
G = Q = Q
1 = C = DI
3 = E = UD
4 = H = UD, DU
D = V = UQ
9 = S = QI
5 = - = DUDU
2 = P = UDDU
B = + = UDUD
A = O = UDQI
7 = A = UQQI
8 = M = DUDUQI
6 = X = UQDUDU
C = T = UQUDUD

修正下 C=DU改成 DI, 因为肽展公式(补码计算) C= DDU, DD是补码

肽展公式的推导(肽展计算)(C=I+D)

开始语义肽展公式验证### 元基数学加法表 根据 4 的归纳完整推导如下

元基数字 = 元基符号= 肽展公式元基变换

0 = D = D + D

1 = C = I + D

2 = P = E + C

3 = E = I + U, D + U

4 = H = E OR C

5 = - = H + C

6 = X = V + HC

7 = A = V + S

8 = M = HC + S

9 = S = Q + I

A = O = E + S

B = + = H + E

C = T = V + HE

D = V = U + Q

E = I = I

F = U = I++ OR Q--

G = Q = Q

###于是元基数字归纳

元基数字 = 元基符号= 肽展公式元基数字变换

0 = D = 0 + 0

1 = C = 1 + 0

2 = P = (12, 02) + 10

3 = E = 1 + 2, 0 + 2

4 = H = (12, 02) OR 10

5 = HC = (12, 02) OR 10 + 10

6 = X = 23 + (12, 02) OR 10 + 10

7 = A = 23 + 31

8 = M = (12, 02) OR 10 + 10 + 31

9 = S = 3 + 1

A = O = (12, 02) + 31

B = HE = (12, 02) OR 10 + 12, 02

C = T = 23 + (12, 02) OR 10 + (12, 02)

D = V = 2 + 3

E = I = 1

F = U = 1++ OR 3--

G = Q = 3

###于是元基肽展归纳如下

元基数字 = 元基符号= 肽展公式元基数字变换

0 = D = D + D

1 = C = I + D

2 = P = (IU, DU) + ID

3 = E = I + U, D + U

4 = H = (IU, DU) OR ID

5 = HC = (IU, DU) OR ID + ID

6 = X = UQ + (IU, DU) OR ID + ID

7 = A = UQ + QI

8 = M = (IU, DU) OR ID + ID + QI

9 = S = Q + I

A = O = (IU, DU) + QI

B = HE = (IU, DU) OR ID + (IU, DU)

C = T = UQ + (IU, DU) OR ID + (IU, DU)

D = V = U + Q

E = I = I

F = U = I++ OR Q--

G = Q = Q

###开始整理

元基数字 = 元基符号= 肽展公式元基数字变换

0 = D = DD

1 = C = ID

2 = P = IUID, DUID

3 = E = IU, DU

4 = H = (IU, DU) OR ID

5 = HC = (IU, DU) OR ID + ID

6 = X = UQ + (IU, DU) OR ID + ID

7 = A = UQQI

8 = M = (IU, DU) OR ID + ID + QI

9 = S = QI

A = O = (IU, DU) + QI

B = HE = (IU, DU) OR ID + (IU, DU)

C = T = UQ + (IU, DU) OR ID + (IU, DU)

D = V = UQ

E = I = I

F = U = I++ OR Q--

G = Q = Q

我得到一个结论,肽展公式的推导(C=I+D)比数字逻辑的推导(C=U+D+D)更准确。

###开始线性整理

元基数字 = 元基符号= 肽展公式元基数字变换

0 = D = DD

E = I = I

F = U = I++ OR Q--

G = Q = Q

1 = C = ID

3 = E = IU, DU

4 = H = (IU, DU) OR ID

D = V = UQ

9 = S = QI

2 = P = (IU, DU) + ID

A = O = (IU, DU) + QI

5 = HC = ((IU, DU) OR ID) + ID

B = HE = ((IU, DU) OR ID) + (IU, DU)

8 = M = ((IU, DU) OR ID) + ID + QI

7 = A = UQQI

6 = X = UQ + ((IU, DU) OR ID) + ID

C = T = UQ + ((IU, DU) OR ID) + (IU, DU)

###线性整理优化

元基数字 = 元基符号= 肽展公式元基数字变换

0 = D = DD

E = I = I

F = U = I++ OR Q--

G = Q = Q

1 = C = ID

3 = E = IU, DU

4 = H = (IU, DU) OR ID

5 = HC = ((IU, DU) OR ID) + ID

B = HE = ((IU, DU) OR ID) + (IU, DU)

D = V = UQ

9 = S = QI

2 = P = (IU, DU) + ID

A = O = (IU, DU) + QI

7 = A = UQQI

8 = M = ((IU, DU) OR ID) + ID + QI

6 = X = UQ + ((IU, DU) OR ID) + ID

C = T = UQ + ((IU, DU) OR ID) + (IU, DU)

我推导出语义元基的次序为

A O P M - T X H DD - V E C S - I D U Q

现在的元基数字逻辑次序为

M X T - P O A - C E H HC HE V S - D I U Q

###酸碱肽展开归纳如下

元基数字 = 元基符号= 肽展公式元基数字变换 = (肽概率展开数字逻辑集合)

0 = D = DD =(D, DD)

E = I = I =(I)

F = U = I++ OR Q-- =(I, Q)

G = Q = Q =(Q)

1 = C = ID =(ID)

3 = E = IU, DU =(IU, DU)

4 = H = (IU, DU) OR ID =(IU, DU, ID)

D = V = UQ =(UQ)

9 = S = QI =(QI)

2 = P = (IU, DU) + ID =(IUID, DUID)

5 = HC = ((IU, DU) OR ID) + ID =(IUID, DUID, IDID)

B = HE = ((IU, DU) OR ID) + (IU, DU) =(IUIU, IUDU, DUIU, DUDU, IDIU, IDDU)

A = O = (IU, DU) + QI =(IUQI, DUQI)

7 = A = UQQI =(UQQI)

8 = M = ((IU, DU) OR ID) + ID + QI =(IUIDQI, DUIDQI, IDIDQI)

6 = X = UQ + ((IU, DU) OR ID) + ID =(UQIUID, UQDUID, UQIDID)

C = T = UQ + ((IU, DU) OR ID) + (IU, DU) =(UQIUIU, UQIUDU, UQDUIU, UQDUDU, UQIDIU, UQIDDU)

归纳后的元基数字逻辑次序为

M X T - P HC HE O A - C E H V S - D I U Q

归纳后的元基数字活性次序为

T X M - HE HC O P A - H E C V S - U D I Q

准备应用于养疗经DNA视觉进行简单验证下,优化后用于DNA数据库的数字层计算。

在这次序表中D在I的前面,于是我准备修正C=ID为DI,于是如下:

修正C后的最新肽展计算公式观测

元基数字 = 元基符号= 肽展公式元基数字变换 = (肽概率展开数字逻辑集合)

0 = D = DD =(D, DD)

E = I = I =(I)

F = U = I++ OR Q-- =(I, Q)

G = Q = Q =(Q)

1 = C = DI =(DI)

3 = E = IU, DU =(IU, DU)

4 = H = (IU, DU) OR DI =(IU, DU, DI)

D = V = UQ =(UQ)

9 = S = QI =(QI)

2 = P = (IU, DU) + DI =(IUDI, DUDI)

5 = HC = ((IU, DU) OR DI) + DI =(IUDI, DUDI, DIDI)

B = HE = ((IU, DU) OR DI) + (IU, DU) =(IUIU, IUDU, DUIU, DUDU, DIIU, DIDU)

A = O = (IU, DU) + QI =(IUQI, DUQI)

7 = A = UQQI =(UQQI)

8 = M = ((IU, DU) OR DI) + DI + QI =(IUDIQI, DUDIQI, DIDIQI)

6 = X = UQ + ((IU, DU) OR DI) + DI =(UQIUDI, UQDUDI, UQDIDI)

C = T = UQ + ((IU, DU) OR DI) + (IU, DU) =(UQIUIU, UQIUDU, UQDUIU, UQDUDU, UQDIIU, UQDIDU)

继续跟进了下在离散数学中 H = (IU, DU) OR DI= (IU, DU) + DI= IUDI, DUDI, 上面的肽展公式在 离散数学中可以继续展开如下

元基数字 = 元基符号= 肽展公式元基数字变换 = (肽概率展开数字逻辑集合)

0 = D = DD =(D, DD)

E = I = I =(I)

F = U = I++ OR Q-- =(I, Q)

G = Q = Q =(Q)

1 = C = DI =(DI)

3 = E = IU, DU =(IU, DU)

4 = H = (IU, DU) OR DI =(IU, DU, DI) OR (IUDI, DUDI)

D = V = UQ =(UQ)

9 = S = QI =(QI)

2 = P = (IU, DU) + DI =(IUDI, DUDI)

5 = HC = ((IU, DU) OR DI) + DI =(IUDI, DUDI, DIDI) OR (IUDIDI, DUDIDI)

B = HE = ((IU, DU) OR DI) + (IU, DU) =(IUIU, IUDU, DUIU, DUDU, DIIU, DIDU) OR (IUDIIU, IUDIDU, DUDIIU, DUDIDU)

A = O = (IU, DU) + QI =(IUQI, DUQI)

7 = A = UQQI =(UQQI)

8 = M = ((IU, DU) OR DI) + DI + QI =(IUDIQI, DUDIQI, DIDIQI) OR (IUDIDIQI, DUDIDIQI)

6 = X = UQ + ((IU, DU) OR DI) + DI =(UQIUDI, UQDUDI, UQDIDI) OR (UQIUDIDI, UQDUDIDI)

C = T = UQ + ((IU, DU) OR DI) + (IU, DU) =(UQIUIU, UQIUDU, UQDUIU, UQDUDU, UQDIIU, UQDIDU) OR (UQIUDIIU, UQIUDIDU, UQDUDIIU, UQDUDIDU)

似乎开始完美。于是活性顺序又打乱了,再整理下如下:

元基数字 = 元基符号= 肽展公式元基数字变换 = (肽概率展开数字逻辑集合)

1位

E = I = I =(I)
F = U = I++ OR Q-- =(I, Q)
G = Q = Q =(Q)

1~2位

0 = D = DD =(D, DD)

2位

1 = C = DI =(DI)
3 = E = IU, DU =(IU, DU)
D = V = UQ =(UQ)
9 = S = QI =(QI)

2~4位

4 = H = (IU, DU) OR DI =(IU, DU, DI) OR (IUDI, DUDI)

4位

2 = P = (IU, DU) + DI =(IUDI, DUDI)
A = O = (IU, DU) + QI =(IUQI, DUQI)
7 = A = UQQI =(UQQI)

4~6位

5 = HC- = ((IU, DU) OR DI) + DI =(IUDI, DUDI, DIDI) OR (IUDIDI, DUDIDI)
B = HE+ = ((IU, DU) OR DI) + (IU, DU) =(IUIU, IUDU, DUIU, DUDU, DIIU, DIDU) OR (IUDIIU, IUDIDU, DUDIIU, DUDIDU)

6~8位

8 = M = ((IU, DU) OR DI) + DI + QI =(IUDIQI, DUDIQI, DIDIQI) OR (IUDIDIQI, DUDIDIQI)
6 = X = UQ + ((IU, DU) OR DI) + DI =(UQIUDI, UQDUDI, UQDIDI) OR (UQIUDIDI, UQDUDIDI)
C = T = UQ + ((IU, DU) OR DI) + (IU, DU) =(UQIUIU, UQIUDU, UQDUIU, UQDUDU, UQDIIU, UQDIDU) OR (UQIUDIIU, UQIUDIDU, UQDUDIIU, UQDUDIDU)

C还是 = DI 次序, 所以上一步的公式不用变动。

整理后:

元基活性次序为 <IUQ D CEVS H POA -+ MXT>

我得到一个结论:IDQ 是稳定元基, UH是活性元基.(2021024 结论更新, IQ是稳定元基, DUH是活性元基)

归纳出核心

黄嘌呤:用于肽展换元 计算
变嘧啶:用于 血氧峰 计算
胞嘧啶:用于 补码 计算

肽展公式参考:

AOPM VECS IDUQ 肽展公式推导与元基编码进化计算以及它的应用发现 1.2.2 国家软著申请 流水号 <2020Z11L0356797> 国作登字 2021-A-00942587 (中华人民共和国 国家版权局)
AOPM-VECS-IDUQ Catalytic INITONS PDE LAW and Its Application
https://gitee.com/DetaChina/collection-of-papers-by-deta/blob/master/%E8%91%97%E4%BD%9C%E6%9D%83%E7%89%88%E6%9C%ACPDE_Formular_1_2_2.pdf
https://github.com/yaoguangluo/Deta_Resource/blob/master/%E8%91%97%E4%BD%9C%E6%9D%83%E7%89%88%E6%9C%ACPDE_Formular_1_2_2.pdf

元基命名参考:

<见类人DNA与 神经元基于催化算子映射编码方式 V_1.2.2版本国家软著申请 流水号 <2020Z11L0333706>
https://gitee.com/DetaChina/collection-of-papers-by-deta/blob/master/DNA%20%E7%BC%96%E7%A0%81%E6%96%B9%E5%BC%8F1.2.2%20%E4%B8%AD%E8%AF%91%E8%8B%B1%E6%B7%B7%E5%90%88%E7%89%88.pdf
https://github.com/yaoguangluo/Deta_Resource/blob/master/DNA%20%E7%BC%96%E7%A0%81%E6%96%B9%E5%BC%8F1.2.2%20%E4%B8%AD%E8%AF%91%E8%8B%B1%E6%B7%B7%E5%90%88%E7%89%88.pdf

DNA 催化 与 肽展计算 和 AOPM-TXH-VECS-IDUQ 元基解码 V013_026中文版本 国家著作申请 流水号 <2020Z11L0386462> 国作登字 2021-A-00942586 (中华人民共和国 国家版权局)

https://github.com/yaoguangluo/Deta_Resource/blob/master/DNA%20Initon%20解码%20013026软著申请中文最终版本.pdf
https://gitee.com/DetaChina/collection-of-papers-by-deta/blob/master/DNA%20Initon%20解码%20013026软著申请中文最终版本.pdf
https://gitee.com/DetaChina/collection-of-papers-by-deta/blob/master/DNA%20Initon%20解码%20013026软著申请中文最终版本%20修正'食'字.pdf
https://github.com/yaoguangluo/Deta_Resource/blob/master/DNA%20Initon%20解码%20013026软著申请中文最终版本%20修正'食'字.pdf

元基欧拉环计算参考:

https://gitee.com/DetaChina/dna_-db/blob/master/Initon_Math/org/math/initon/ouler/FindOulerRing.java

双元罗盘参考:

多人著作(罗瑶光, 罗荣武) DNA元基催化与肽计算第二卷 养疗经应用研究 20210305 国家著作申请 流水号 <2021Z11L1057159>
https://gitee.com/DetaChina/collection-of-papers-by-deta/blob/master/罗瑶光-DNA催化与肽计算第二卷20210305.pdf
https://github.com/yaoguangluo/Deta_Catalytic_DNA/blob/master/罗瑶光-DNA催化与肽计算第二卷20210305.pdf

走到这,元基数学 公式表已经出来了,下一步就开始简单应用。

Yaoguang.Luo

罗瑶光

正在 将 eclipse 的工程往 idea上 部署调试。看了下 license, 教育版是侵权版本。 又改回eclipse
GNU GENERAL PUBLIC LICENSE Version 2, June 1991 Copyright (C) 1989, 1991 Free Software Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA Everyone is permitted to copy and distribute verbatim copies of this license document, but changing it is not allowed. Preamble The licenses for most software are designed to take away your freedom to share and change it. By contrast, the GNU General Public License is intended to guarantee your freedom to share and change free software--to make sure the software is free for all its users. This General Public License applies to most of the Free Software Foundation's software and to any other program whose authors commit to using it. (Some other Free Software Foundation software is covered by the GNU Lesser General Public License instead.) You can apply it to your programs, too. When we speak of free software, we are referring to freedom, not price. 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IN NO EVENT UNLESS REQUIRED BY APPLICABLE LAW OR AGREED TO IN WRITING WILL ANY COPYRIGHT HOLDER, OR ANY OTHER PARTY WHO MAY MODIFY AND/OR REDISTRIBUTE THE PROGRAM AS PERMITTED ABOVE, BE LIABLE TO YOU FOR DAMAGES, INCLUDING ANY GENERAL, SPECIAL, INCIDENTAL OR CONSEQUENTIAL DAMAGES ARISING OUT OF THE USE OR INABILITY TO USE THE PROGRAM (INCLUDING BUT NOT LIMITED TO LOSS OF DATA OR DATA BEING RENDERED INACCURATE OR LOSSES SUSTAINED BY YOU OR THIRD PARTIES OR A FAILURE OF THE PROGRAM TO OPERATE WITH ANY OTHER PROGRAMS), EVEN IF SUCH HOLDER OR OTHER PARTY HAS BEEN ADVISED OF THE POSSIBILITY OF SUCH DAMAGES. END OF TERMS AND CONDITIONS How to Apply These Terms to Your New Programs If you develop a new program, and you want it to be of the greatest possible use to the public, the best way to achieve this is to make it free software which everyone can redistribute and change under these terms. To do so, attach the following notices to the program. It is safest to attach them to the start of each source file to most effectively convey the exclusion of warranty; and each file should have at least the "copyright" line and a pointer to where the full notice is found. <one line to give the program's name and a brief idea of what it does.> Copyright (C) <year> <name of author> This program is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 2 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program; if not, write to the Free Software Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA. Also add information on how to contact you by electronic and paper mail. If the program is interactive, make it output a short notice like this when it starts in an interactive mode: Gnomovision version 69, Copyright (C) year name of author Gnomovision comes with ABSOLUTELY NO WARRANTY; for details type `show w'. This is free software, and you are welcome to redistribute it under certain conditions; type `show c' for details. The hypothetical commands `show w' and `show c' should show the appropriate parts of the General Public License. Of course, the commands you use may be called something other than `show w' and `show c'; they could even be mouse-clicks or menu items--whatever suits your program. You should also get your employer (if you work as a programmer) or your school, if any, to sign a "copyright disclaimer" for the program, if necessary. Here is a sample; alter the names: Yoyodyne, Inc., hereby disclaims all copyright interest in the program `Gnomovision' (which makes passes at compilers) written by James Hacker. <signature of Ty Coon>, 1 April 1989 Ty Coon, President of Vice This General Public License does not permit incorporating your program into proprietary programs. If your program is a subroutine library, you may consider it more useful to permit linking proprietary applications with the library. If this is what you want to do, use the GNU Lesser General Public License instead of this License.

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德塔Socket流可编程数据库语言引擎系统(Deta PLSQL Database)的 DNA催化计算版本 展开 收起
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GPL-2.0
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