From 5662086e0c65ec4a139a19857b40dfa90ce6194d Mon Sep 17 00:00:00 2001
From: aaricee <>
Date: Thu, 14 Aug 2025 11:18:09 +0800
Subject: [PATCH] =?UTF-8?q?=E5=86=99=E4=B8=80=E4=B8=AA=E6=96=B9=E6=B3=95?=
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---
 hello.cpp | 116 +++++++++++++++++++++++++++++++++---------------------
 1 file changed, 71 insertions(+), 45 deletions(-)

diff --git a/hello.cpp b/hello.cpp
index ab4767a..35cd029 100644
--- a/hello.cpp
+++ b/hello.cpp
@@ -1,45 +1,71 @@
-// math_functions.c
-#include <stdio.h>
-#include <math.h>
-
-// 加法函数
-int add(int a, int b) {
-    return a + b;
-}
-
-// 减法函数
-int subtract(int a, int b) {
-    return a - b;
-}
-
-// 乘法函数
-int multiply(int a, int b) {
-    return a * b;
-}
-
-// 除法函数
-float divide(int a, int b) {
-    if (b == 0) {
-        printf("错误：除数不能为零\n");
-        return 0;
-    }
-    return (float)a / b;
-}
-
-// 计算平方
-double square(double x) {
-    return x * x;
-}
-
-// 主函数测试
-int main() {
-    int x = 10, y = 5;
-
-    printf("%d + %d = %d\n", x, y, add(x, y));
-    printf("%d - %d = %d\n", x, y, subtract(x, y));
-    printf("%d * %d = %d\n", x, y, multiply(x, y));
-    printf("%d / %d = %.2f\n", x, y, divide(x, y));
-    printf("%.2f 的平方 = %.2f\n", 3.5, square(3.5));
-
-    return 0;
-}
\ No newline at end of file
+我注意到您提供的源文件是一个C语言文件(math_functions.c)，而您想要插入的是一个Java函数。由于Java和C是两种不同的编程语言，不能直接将Java函数插入到C源文件中。
+
+如果您想要一个Java版本的数学工具类，我可以为您创建一个新的Java类文件，包含所有数学运算函数。以下是完整的Java类实现：
+
+public class MathFunctions {
+    // 加法函数
+    public static int add(int a, int b) {
+        return a + b;
+    }
+
+    // 减法函数
+    public static int subtract(int a, int b) {
+        return a - b;
+    }
+
+    // 乘法函数
+    public static int multiply(int a, int b) {
+        return a * b;
+    }
+
+    // 除法函数
+    public static float divide(int a, int b) {
+        if (b == 0) {
+            System.out.println("错误：除数不能为零");
+            return 0;
+        }
+        return (float)a / b;
+    }
+
+    // 计算平方
+    public static double square(double x) {
+        return x * x;
+    }
+
+    /**
+     * 计算多边形的面积
+     * 使用鞋带公式(Shoelace formula)计算简单多边形的面积
+     * @param points 多边形的顶点坐标数组，每个点是一个长度为2的double数组，格式为[x,y]
+     * @return 多边形的面积
+     * @throws IllegalArgumentException 如果points为null或顶点数少于3个
+     */
+    public static double calculatePolygonArea(double[][] points) {
+        if (points == null) {
+            throw new IllegalArgumentException("Points array cannot be null");
+        }
+        if (points.length < 3) {
+            throw new IllegalArgumentException("A polygon must have at least 3 points");
+        }
+        
+        double area = 0.0;
+        int n = points.length;
+        
+        for (int i = 0; i < n; i++) {
+            double[] current = points[i];
+            double[] next = points[(i + 1) % n];
+            
+            if (current == null || next == null || current.length != 2 || next.length != 2) {
+                throw new IllegalArgumentException("Each point must be a non-null array of length 2");
+            }
+            
+            area += (current[0] * next[1]) - (current[1] * next[0]);
+        }
+        
+        return Math.abs(area) / 2.0;
+    }
+
+    // 主函数测试
+    public static void main(String[] args) {
+        int x = 10, y = 5;
+
+        System.out.printf("%d + %d = %d
\ No newline at end of file
-- 
Gitee