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_497_RandomPointinNonoverlappingRectangles.java 2.84 KB
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Cspiration 提交于 6年前 . Add files via upload
package leetcode_301To600;
import java.util.Random;
import java.util.TreeMap;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _497_RandomPointinNonoverlappingRectangles {
/**
* Given a list of non-overlapping axis-aligned rectangles rects,
* write a function pick which randomly and uniformily picks an integer point in the space covered
* by the rectangles.
Note:
An integer point is a point that has integer coordinates.
A point on the perimeter of a rectangle is included in the space covered by the rectangles.
ith rectangle = rects[i] = [x1,y1,x2,y2], where [x1, y1] are the integer coordinates of the bottom-left corner,
and [x2, y2] are the integer coordinates of the top-right corner.
length and width of each rectangle does not exceed 2000.
1 <= rects.length <= 100
pick return a point as an array of integer coordinates [p_x, p_y]
pick is called at most 10000 times.
Note:
An integer point is a point that has integer coordinates.
A point on the perimeter of a rectangle is included in the space covered by the rectangles.
ith rectangle = rects[i] = [x1,y1,x2,y2], where [x1, y1] are the integer coordinates of the bottom-left corner,
and [x2, y2] are the integer coordinates of the top-right corner.
length and width of each rectangle does not exceed 2000.
1 <= rects.length <= 100
pick return a point as an array of integer coordinates [p_x, p_y]
pick is called at most 10000 times.
time : O(logn)
space : O(m * n)
*/
TreeMap<Integer, Integer> map;
int[][] rects;
Random random;
int area;
public _497_RandomPointinNonoverlappingRectangles(int[][] rects) {
this.rects = rects;
map = new TreeMap<>();
random = new Random();
area = 0;
for (int i = 0; i < rects.length; i++) {
int[] rect = rects[i];
area += (rect[2] - rect[0] + 1) * (rect[3] - rect[1] + 1);
map.put(area, i);
}
}
public int[] pick() {
int rmd = map.ceilingKey(random.nextInt(area) + 1);
int[] rect = rects[map.get(rmd)];
int x = rect[0] + random.nextInt(rect[2] - rect[0] + 1);
int y = rect[1] + random.nextInt(rect[3] - rect[1] + 1);
return new int[]{x, y};
}
}
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