# python-zipstream **Repository Path**: qop6666/python-zipstream ## Basic Information - **Project Name**: python-zipstream - **Description**: forked from allanlei/python-zipstream - **Primary Language**: Unknown - **License**: GPL-3.0 - **Default Branch**: master - **Homepage**: None - **GVP Project**: No ## Statistics - **Stars**: 0 - **Forks**: 0 - **Created**: 2020-02-16 - **Last Updated**: 2020-12-18 ## Categories & Tags **Categories**: Uncategorized **Tags**: None ## README # Enczipstream [![Build Status](https://travis-ci.org/ch0k0bn/python-zipstream.png?branch=master)](https://travis-ci.org/ch0k0bn/python-zipstream) ## Original Authors and Weak algorithm warning enczipstream is the merge between allanlei's [python-zipstream](https://github.com/allanlei/python-zipstream) and devthat's [zipencrypt](https://github.com/devthat/zipencrypt/tree/master/zipencrypt) allowing a user to stream password protected archive (with the weak algorithm) WEAK ALGORITHM IS NOT SECURE ## Readme enczipstream.py is a zip archive generator based on python 3.3's zipfile.py. It was created to generate a zip file generator for streaming (ie web apps). This is beneficial for when you want to provide a downloadable archive of a large collection of regular files, which would be infeasible to generate the archive prior to downloading or of a very large file that you do not want to store entirely on disk or on memory. The archive is generated as an iterator of strings, which, when joined, form the zip archive. For example, the following code snippet would write a zip archive containing files from 'path' to a normal file: ```python import enczipstream z = enczipstream.ZipFile() z.write('path/to/files') with open('zipfile.zip', 'wb') as f: for data in z: f.write(data) ``` enczipstream also allows to take as input a byte string iterable and to generate the archive as an iterator. This avoids storing large files on disk or in memory. To do so you could use something like this snippet: ```python def iterable(): for _ in xrange(10): yield b'this is a byte string\x01\n' z = enczipstream.ZipFile() z.write_iter('my_archive_iter', iterable()) with open('zipfile.zip', 'wb') as f: for data in z: f.write(data) ``` Of course both approach can be combined: ```python def iterable(): for _ in xrange(10): yield b'this is a byte string\x01\n' z = enczipstream.ZipFile() z.write('path/to/files', 'my_archive_files') z.write_iter('my_archive_iter', iterable()) with open('zipfile.zip', 'wb') as f: for data in z: f.write(data) ``` Since recent versions of web.py support returning iterators of strings to be sent to the browser, to download a dynamically generated archive, you could use something like this snippet: ```python def GET(self): path = '/path/to/dir/of/files' zip_filename = 'files.zip' web.header('Content-type' , 'application/zip') web.header('Content-Disposition', 'attachment; filename="%s"' % ( zip_filename,)) return enczipstream.ZipFile(path) ``` If the zlib module is available, enczipstream.ZipFile can generate compressed zip archives. ## Installation ``` pip install enczipstream ``` ## Requirements * Python 2.6, 2.7, 3.2, 3.3, pypy ## Examples ### flask ```python from flask import Response @app.route('/package.zip', methods=['GET'], endpoint='zipball') def zipball(): def generator(): z = enczipstream.ZipFile(mode='w', compression=ZIP_DEFLATED) z.write('/path/to/file') for chunk in z: yield chunk response = Response(generator(), mimetype='application/zip') response.headers['Content-Disposition'] = 'attachment; filename={}'.format('files.zip') return response # or @app.route('/package.zip', methods=['GET'], endpoint='zipball') def zipball(): z = enczipstream.ZipFile(mode='w', compression=ZIP_DEFLATED) z.write('/path/to/file') response = Response(z, mimetype='application/zip') response.headers['Content-Disposition'] = 'attachment; filename={}'.format('files.zip') return response ``` ### django 1.5+ ```python from django.http import StreamingHttpResponse def zipball(request): z = enczipstream.ZipFile(mode='w', compression=ZIP_DEFLATED) z.write('/path/to/file') response = StreamingHttpResponse(z, content_type='application/zip') response['Content-Disposition'] = 'attachment; filename={}'.format('files.zip') return response ``` ### webpy ```python def GET(self): path = '/path/to/dir/of/files' zip_filename = 'files.zip' web.header('Content-type' , 'application/zip') web.header('Content-Disposition', 'attachment; filename="%s"' % ( zip_filename,)) return enczipstream.ZipFile(path) ``` ### password example ```python def iterable(): for _ in xrange(10): yield b'this is a byte string\x01\n' z = enczipstream.ZipFile(mode='w', compression=enczipstream.ZIP_DEFLATED, pwd=b"correct horse battery staple") z.write_iter('my_archive_iter', iterable()) ``` ## Running tests With python version > 2.6, just run the following command: `python -m unittest discover` Alternatively, you can use `nose`.