Ai
2 Star 0 Fork 0

CS-IMIS-23/20172302侯泽洋

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
该仓库未声明开源许可证文件(LICENSE),使用请关注具体项目描述及其代码上游依赖。
克隆/下载
PostfixEvaluator.java 2.45 KB
一键复制 编辑 原始数据 按行查看 历史
20172302 提交于 2018-10-27 20:30 +08:00 . 第十章——树课本代码及课本练习题
package chapter10;
import chapter10.jsjf.BinaryTreeNode;
import java.util.*;
public class PostfixEvaluator {
private String expression;
private Stack<ExpressionTree> treeStack;
/**
* Sets up this evalutor by creating a new stack.
*/
public PostfixEvaluator()
{
treeStack = new Stack<ExpressionTree>();
}
/**
* Retrieves and returns the next operand off of this tree stack.
*
* @param treeStack the tree stack from which the operand will be returned
* @return the next operand off of this tree stack
*/
private ExpressionTree getOperand(Stack<ExpressionTree> treeStack)
{
ExpressionTree temp;
temp = treeStack.pop();
return temp;
}
/**
* Evaluates the specified postfix expression by building and evaluating
* an expression tree.
*
* @param expression string representation of a postfix expression
* @return value of the given expression
*/
public int evaluate(String expression)
{
ExpressionTree operand1, operand2;
char operator;
String tempToken;
Scanner parser = new Scanner(expression);
while (parser.hasNext())
{
tempToken = parser.next();
operator = tempToken.charAt(0);
if ((operator == '+') || (operator == '-') || (operator == '*') ||
(operator == '/'))
{
operand1 = getOperand(treeStack);
operand2 = getOperand(treeStack);
treeStack.push(new ExpressionTree(new ExpressionTreeOp(1,operator,0), operand2, operand1));
}
else
{
treeStack.push(new ExpressionTree(new ExpressionTreeOp
(2,' ',Integer.parseInt(tempToken)), null, null));
}
}
return (treeStack.peek()).evaluateTree();
}
/**
* Returns the expression tree associated with this postfix evaluator.
*
* @return string representing the expression tree
*/
public String getTree()
{
return (treeStack.peek()).printTree();
}
public void removeAllElements()
{
treeStack.peek().removeAllElements();
}
public boolean contains(ExpressionTreeOp expressionTreeOp)
{
return (treeStack.peek()).contains(expressionTreeOp);
}
public BinaryTreeNode<ExpressionTreeOp> getRoot()
{
return (treeStack.peek()).getRootNode();
}
}
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
Java
1
https://gitee.com/CS-IMIS-23/Java-pro.git
git@gitee.com:CS-IMIS-23/Java-pro.git
CS-IMIS-23
Java-pro
20172302侯泽洋
master

搜索帮助