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编程语言算法集 / Python

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trifid_cipher.py 6.84 KB
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"""
The trifid cipher uses a table to fractionate each plaintext letter into a trigram,
mixes the constituents of the trigrams, and then applies the table in reverse to turn
these mixed trigrams into ciphertext letters.
https://en.wikipedia.org/wiki/Trifid_cipher
"""
from __future__ import annotations
# fmt: off
TEST_CHARACTER_TO_NUMBER = {
"A": "111", "B": "112", "C": "113", "D": "121", "E": "122", "F": "123", "G": "131",
"H": "132", "I": "133", "J": "211", "K": "212", "L": "213", "M": "221", "N": "222",
"O": "223", "P": "231", "Q": "232", "R": "233", "S": "311", "T": "312", "U": "313",
"V": "321", "W": "322", "X": "323", "Y": "331", "Z": "332", "+": "333",
}
# fmt: off
TEST_NUMBER_TO_CHARACTER = {val: key for key, val in TEST_CHARACTER_TO_NUMBER.items()}
def __encrypt_part(message_part: str, character_to_number: dict[str, str]) -> str:
"""
Arrange the triagram value of each letter of 'message_part' vertically and join
them horizontally.
>>> __encrypt_part('ASK', TEST_CHARACTER_TO_NUMBER)
'132111112'
"""
one, two, three = "", "", ""
for each in (character_to_number[character] for character in message_part):
one += each[0]
two += each[1]
three += each[2]
return one + two + three
def __decrypt_part(
message_part: str, character_to_number: dict[str, str]
) -> tuple[str, str, str]:
"""
Convert each letter of the input string into their respective trigram values, join
them and split them into three equal groups of strings which are returned.
>>> __decrypt_part('ABCDE', TEST_CHARACTER_TO_NUMBER)
('11111', '21131', '21122')
"""
this_part = "".join(character_to_number[character] for character in message_part)
result = []
tmp = ""
for digit in this_part:
tmp += digit
if len(tmp) == len(message_part):
result.append(tmp)
tmp = ""
return result[0], result[1], result[2]
def __prepare(
message: str, alphabet: str
) -> tuple[str, str, dict[str, str], dict[str, str]]:
"""
A helper function that generates the triagrams and assigns each letter of the
alphabet to its corresponding triagram and stores this in a dictionary
("character_to_number" and "number_to_character") after confirming if the
alphabet's length is 27.
>>> test = __prepare('I aM a BOy','abCdeFghijkLmnopqrStuVwxYZ+')
>>> expected = ('IAMABOY','ABCDEFGHIJKLMNOPQRSTUVWXYZ+',
... TEST_CHARACTER_TO_NUMBER, TEST_NUMBER_TO_CHARACTER)
>>> test == expected
True
Testing with incomplete alphabet
>>> __prepare('I aM a BOy','abCdeFghijkLmnopqrStuVw')
Traceback (most recent call last):
...
KeyError: 'Length of alphabet has to be 27.'
Testing with extra long alphabets
>>> __prepare('I aM a BOy','abCdeFghijkLmnopqrStuVwxyzzwwtyyujjgfd')
Traceback (most recent call last):
...
KeyError: 'Length of alphabet has to be 27.'
Testing with punctuations that are not in the given alphabet
>>> __prepare('am i a boy?','abCdeFghijkLmnopqrStuVwxYZ+')
Traceback (most recent call last):
...
ValueError: Each message character has to be included in alphabet!
Testing with numbers
>>> __prepare(500,'abCdeFghijkLmnopqrStuVwxYZ+')
Traceback (most recent call last):
...
AttributeError: 'int' object has no attribute 'replace'
"""
# Validate message and alphabet, set to upper and remove spaces
alphabet = alphabet.replace(" ", "").upper()
message = message.replace(" ", "").upper()
# Check length and characters
if len(alphabet) != 27:
raise KeyError("Length of alphabet has to be 27.")
if any(char not in alphabet for char in message):
raise ValueError("Each message character has to be included in alphabet!")
# Generate dictionares
character_to_number = dict(zip(alphabet, TEST_CHARACTER_TO_NUMBER.values()))
number_to_character = {
number: letter for letter, number in character_to_number.items()
}
return message, alphabet, character_to_number, number_to_character
def encrypt_message(
message: str, alphabet: str = "ABCDEFGHIJKLMNOPQRSTUVWXYZ.", period: int = 5
) -> str:
"""
encrypt_message
===============
Encrypts a message using the trifid_cipher. Any punctuatuions that
would be used should be added to the alphabet.
PARAMETERS
----------
* message: The message you want to encrypt.
* alphabet (optional): The characters to be used for the cipher .
* period (optional): The number of characters you want in a group whilst
encrypting.
>>> encrypt_message('I am a boy')
'BCDGBQY'
>>> encrypt_message(' ')
''
>>> encrypt_message(' aide toi le c iel ta id era ',
... 'FELIXMARDSTBCGHJKNOPQUVWYZ+',5)
'FMJFVOISSUFTFPUFEQQC'
"""
message, alphabet, character_to_number, number_to_character = __prepare(
message, alphabet
)
encrypted_numeric = ""
for i in range(0, len(message) + 1, period):
encrypted_numeric += __encrypt_part(
message[i : i + period], character_to_number
)
encrypted = ""
for i in range(0, len(encrypted_numeric), 3):
encrypted += number_to_character[encrypted_numeric[i : i + 3]]
return encrypted
def decrypt_message(
message: str, alphabet: str = "ABCDEFGHIJKLMNOPQRSTUVWXYZ.", period: int = 5
) -> str:
"""
decrypt_message
===============
Decrypts a trifid_cipher encrypted message .
PARAMETERS
----------
* message: The message you want to decrypt .
* alphabet (optional): The characters used for the cipher.
* period (optional): The number of characters used in grouping when it
was encrypted.
>>> decrypt_message('BCDGBQY')
'IAMABOY'
Decrypting with your own alphabet and period
>>> decrypt_message('FMJFVOISSUFTFPUFEQQC','FELIXMARDSTBCGHJKNOPQUVWYZ+',5)
'AIDETOILECIELTAIDERA'
"""
message, alphabet, character_to_number, number_to_character = __prepare(
message, alphabet
)
decrypted_numeric = []
for i in range(0, len(message), period):
a, b, c = __decrypt_part(message[i : i + period], character_to_number)
for j in range(len(a)):
decrypted_numeric.append(a[j] + b[j] + c[j])
return "".join(number_to_character[each] for each in decrypted_numeric)
if __name__ == "__main__":
import doctest
doctest.testmod()
msg = "DEFEND THE EAST WALL OF THE CASTLE."
encrypted = encrypt_message(msg, "EPSDUCVWYM.ZLKXNBTFGORIJHAQ")
decrypted = decrypt_message(encrypted, "EPSDUCVWYM.ZLKXNBTFGORIJHAQ")
print(f"Encrypted: {encrypted}\nDecrypted: {decrypted}")
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