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编程语言算法集 / Python

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swap_nodes.py 4.20 KB
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from __future__ import annotations
from collections.abc import Iterator
from dataclasses import dataclass
from typing import Any
@dataclass
class Node:
data: Any
next_node: Node | None = None
@dataclass
class LinkedList:
head: Node | None = None
def __iter__(self) -> Iterator:
"""
>>> linked_list = LinkedList()
>>> list(linked_list)
[]
>>> linked_list.push(0)
>>> tuple(linked_list)
(0,)
"""
node = self.head
while node:
yield node.data
node = node.next_node
def __len__(self) -> int:
"""
>>> linked_list = LinkedList()
>>> len(linked_list)
0
>>> linked_list.push(0)
>>> len(linked_list)
1
"""
return sum(1 for _ in self)
def push(self, new_data: Any) -> None:
"""
Add a new node with the given data to the beginning of the Linked List.
Args:
new_data (Any): The data to be added to the new node.
Returns:
None
Examples:
>>> linked_list = LinkedList()
>>> linked_list.push(5)
>>> linked_list.push(4)
>>> linked_list.push(3)
>>> linked_list.push(2)
>>> linked_list.push(1)
>>> list(linked_list)
[1, 2, 3, 4, 5]
"""
new_node = Node(new_data)
new_node.next_node = self.head
self.head = new_node
def swap_nodes(self, node_data_1: Any, node_data_2: Any) -> None:
"""
Swap the positions of two nodes in the Linked List based on their data values.
Args:
node_data_1: Data value of the first node to be swapped.
node_data_2: Data value of the second node to be swapped.
Note:
If either of the specified data values isn't found then, no swapping occurs.
Examples:
When both values are present in a linked list.
>>> linked_list = LinkedList()
>>> linked_list.push(5)
>>> linked_list.push(4)
>>> linked_list.push(3)
>>> linked_list.push(2)
>>> linked_list.push(1)
>>> list(linked_list)
[1, 2, 3, 4, 5]
>>> linked_list.swap_nodes(1, 5)
>>> tuple(linked_list)
(5, 2, 3, 4, 1)
When one value is present and the other isn't in the linked list.
>>> second_list = LinkedList()
>>> second_list.push(6)
>>> second_list.push(7)
>>> second_list.push(8)
>>> second_list.push(9)
>>> second_list.swap_nodes(1, 6) is None
True
When both values are absent in the linked list.
>>> second_list = LinkedList()
>>> second_list.push(10)
>>> second_list.push(9)
>>> second_list.push(8)
>>> second_list.push(7)
>>> second_list.swap_nodes(1, 3) is None
True
When linkedlist is empty.
>>> second_list = LinkedList()
>>> second_list.swap_nodes(1, 3) is None
True
Returns:
None
"""
if node_data_1 == node_data_2:
return
node_1 = self.head
while node_1 and node_1.data != node_data_1:
node_1 = node_1.next_node
node_2 = self.head
while node_2 and node_2.data != node_data_2:
node_2 = node_2.next_node
if node_1 is None or node_2 is None:
return
# Swap the data values of the two nodes
node_1.data, node_2.data = node_2.data, node_1.data
if __name__ == "__main__":
"""
Python script that outputs the swap of nodes in a linked list.
"""
from doctest import testmod
testmod()
linked_list = LinkedList()
for i in range(5, 0, -1):
linked_list.push(i)
print(f"Original Linked List: {list(linked_list)}")
linked_list.swap_nodes(1, 4)
print(f"Modified Linked List: {list(linked_list)}")
print("After swapping the nodes whose data is 1 and 4.")
Python
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Python
Python
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