HttpFile 可以支持stream吗？对于大文件一次性读入 byte[] 并不是好的选择

输入图片说明

就不能好好发 Issue 吗？下次好好发，不过你这个需求非常合理，我下个版本实现。

已经实现，4219557 下个版本发布。

以下是字符串拓展、代理方式的使用，包含 单文件，多文件

单文件上传

字符串方式

var fileStream = new FileStream("image.png", FileMode.Open);

var result = await "https://localhost:44316/api/test-module/upload-file"
                    .SetContentType("multipart/form-data")
                    .SetFiles(HttpFile.Create("file", fileStream, "image.png")).PostAsync();

var fileName = await result.Content.ReadAsStringAsync();

await fileStream.DisposeAsync();

代理方式

var fileStream = new FileStream("image.png", FileMode.Open);

var result = await _http.TestSingleFileProxyAsync(HttpFile.Create("file", fileStream, "image.png"));
var fileName = await result.Content.ReadAsStringAsync();

await fileStream.DisposeAsync();

多文件上传

字符串方式

var fileStream = new FileStream("image.png", FileMode.Open);

var result = await "https://localhost:44316/api/test-module/upload-muliti-file"
                    .SetContentType("multipart/form-data")
                    .SetFiles(HttpFile.CreateMultiple("files", (fileStream, "image1.png"), (fileStream, "image2.png"))).PostAsync();
var fileName = await result.Content.ReadAsStringAsync();

await fileStream.DisposeAsync();

代理方式

var fileStream = new FileStream("image.png", FileMode.Open);

var result = await _http.TestMultiFileProxyAsync(HttpFile.CreateMultiple("files", (fileStream, "image1.png"), (fileStream, "image2.png")));
var fileName = await result.Content.ReadAsStringAsync();

await fileStream.DisposeAsync();

还支持 Bytes 和 Stream 混合

var fileStream = new FileStream("image.png", FileMode.Open);
var bytes = File.ReadAllBytes("image.png");

var httpFile = new HttpFile
{
    Name = name,
    Bytes = bytes,
    FileStream = fileStream,
    FileName = fileName
};

var result = await "https://localhost:44316/api/test-module/upload-file"
                    .SetContentType("multipart/form-data")
                    .SetFiles(httpFile).PostAsync();

var fileName = await result.Content.ReadAsStringAsync();

await fileStream.DisposeAsync();