代码拉取完成,页面将自动刷新
# $571. 给定数字的频率查询中位数
# https://leetcode-cn.com/problems/find-median-given-frequency-of-numbers/
# SQL架构
Create table If Not Exists Numbers (num int, frequency int);
Truncate table Numbers;
insert into Numbers (num, frequency) values ('0', '7');
insert into Numbers (num, frequency) values ('1', '1');
insert into Numbers (num, frequency) values ('2', '3');
insert into Numbers (num, frequency) values ('3', '1');
# Write your MySQL query statement below
select
avg(num) as median
from
(
select
num,
frequency,
sum(frequency) over (
order by
num desc
) s1,
sum(frequency) over (
order by
num asc
) s2,
sum(frequency) over () s3
from
Numbers
) exp
where
s1 >= s3 / 2
and s2 >= s3 / 2;
# clean-up
drop table Numbers;
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。