1 Star 0 Fork 0

逸扬/leetcode-hub-mysql

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
该仓库未声明开源许可证文件(LICENSE),使用请关注具体项目描述及其代码上游依赖。
克隆/下载
lc-0607.test 2.18 KB
一键复制 编辑 原始数据 按行查看 历史
逸扬 提交于 3年前 . fix lc-0607.test
# 607. 销售员
# https://leetcode-cn.com/problems/sales-person/
# SQL架构
Create table If Not Exists SalesPerson (sales_id int, name varchar(255), salary int, commission_rate int, hire_date date);
Create table If Not Exists Company (com_id int, name varchar(255), city varchar(255));
Create table If Not Exists Orders (order_id int, order_date date, com_id int, sales_id int, amount int);
Truncate table SalesPerson;
insert into SalesPerson (sales_id, name, salary, commission_rate, hire_date) values ('1', 'John', '100000', '6', '2006-04-01');
insert into SalesPerson (sales_id, name, salary, commission_rate, hire_date) values ('2', 'Amy', '12000', '5', '2010-05-01');
insert into SalesPerson (sales_id, name, salary, commission_rate, hire_date) values ('3', 'Mark', '65000', '12', '2008-12-25');
insert into SalesPerson (sales_id, name, salary, commission_rate, hire_date) values ('4', 'Pam', '25000', '25', '2005-01-01');
insert into SalesPerson (sales_id, name, salary, commission_rate, hire_date) values ('5', 'Alex', '5000', '10', '2007-02-03');
Truncate table Company;
insert into Company (com_id, name, city) values ('1', 'RED', 'Boston');
insert into Company (com_id, name, city) values ('2', 'ORANGE', 'New York');
insert into Company (com_id, name, city) values ('3', 'YELLOW', 'Boston');
insert into Company (com_id, name, city) values ('4', 'GREEN', 'Austin');
Truncate table Orders;
insert into Orders (order_id, order_date, com_id, sales_id, amount) values ('1', '2014-01-01', '3', '4', '10000');
insert into Orders (order_id, order_date, com_id, sales_id, amount) values ('2', '2014-02-01', '4', '5', '5000');
insert into Orders (order_id, order_date, com_id, sales_id, amount) values ('3', '2014-03-01', '1', '1', '50000');
insert into Orders (order_id, order_date, com_id, sales_id, amount) values ('4', '2014-04-01', '1', '4', '25000');
# Write your MySQL query statement below
select
s.name as name
from
SalesPerson s
where
s.sales_id not in(
select
o.sales_id
from
Orders o
left join Company c on o.com_id = c.com_id
where
c.name = 'RED'
);
# clean-up
drop table SalesPerson;
drop table Company;
drop table Orders;
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
1
https://gitee.com/gdut_yy/leetcode-hub-mysql.git
git@gitee.com:gdut_yy/leetcode-hub-mysql.git
gdut_yy
leetcode-hub-mysql
leetcode-hub-mysql
master

搜索帮助