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# $1270. 向公司CEO汇报工作的所有人
# https://leetcode-cn.com/problems/all-people-report-to-the-given-manager/
# SQL架构
Create table If Not Exists Employees (employee_id int, employee_name varchar(30), manager_id int);
Truncate table Employees;
insert into Employees (employee_id, employee_name, manager_id) values ('1', 'Boss', '1');
insert into Employees (employee_id, employee_name, manager_id) values ('3', 'Alice', '3');
insert into Employees (employee_id, employee_name, manager_id) values ('2', 'Bob', '1');
insert into Employees (employee_id, employee_name, manager_id) values ('4', 'Daniel', '2');
insert into Employees (employee_id, employee_name, manager_id) values ('7', 'Luis', '4');
insert into Employees (employee_id, employee_name, manager_id) values ('8', 'John', '3');
insert into Employees (employee_id, employee_name, manager_id) values ('9', 'Angela', '8');
insert into Employees (employee_id, employee_name, manager_id) values ('77', 'Robert', '1');
# Write your MySQL query statement below
select
distinct employee_id
from
(
select
employee_id
from
Employees
where
manager_id = 1
union
all
select
employee_id
from
Employees
where
manager_id in (
select
employee_id
from
Employees
where
manager_id = 1
)
union
all
select
employee_id
from
Employees
where
manager_id in (
select
employee_id
from
Employees
where
manager_id in (
select
employee_id
from
Employees
where
manager_id = 1
)
)
) tmp
where
employee_id != 1;
# clean-up
drop table Employees;
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