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lc-1587.test 1.59 KB
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逸扬 提交于 3年前 . sql_mode=only_full_group_by
# 1587. 银行账户概要 II
# https://leetcode-cn.com/problems/bank-account-summary-ii/
# SQL架构
Create table If Not Exists Users (account int, name varchar(20));
Create table If Not Exists Transactions (trans_id int, account int, amount int, transacted_on date);
Truncate table Users;
insert into Users (account, name) values ('900001', 'Alice');
insert into Users (account, name) values ('900002', 'Bob');
insert into Users (account, name) values ('900003', 'Charlie');
Truncate table Transactions;
insert into Transactions (trans_id, account, amount, transacted_on) values ('1', '900001', '7000', '2020-08-01');
insert into Transactions (trans_id, account, amount, transacted_on) values ('2', '900001', '7000', '2020-09-01');
insert into Transactions (trans_id, account, amount, transacted_on) values ('3', '900001', '-3000', '2020-09-02');
insert into Transactions (trans_id, account, amount, transacted_on) values ('4', '900002', '1000', '2020-09-12');
insert into Transactions (trans_id, account, amount, transacted_on) values ('5', '900003', '6000', '2020-08-07');
insert into Transactions (trans_id, account, amount, transacted_on) values ('6', '900003', '6000', '2020-09-07');
insert into Transactions (trans_id, account, amount, transacted_on) values ('7', '900003', '-4000', '2020-09-11');
# Write your MySQL query statement below
select
u.name,
sum(t.amount) as balance
from
Transactions t
inner join Users u on t.account = u.account
group by
u.account,
# sql_mode=only_full_group_by
u.name
having
sum(t.amount) > 10000;
# clean-up
drop table Users;
drop table Transactions;
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