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<p>字数统计:</p>
<p>170字</p>
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<p>阅读时长≈</p>
<p>1分</p>
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<a href="/blog/2020/06/07/%5B%E8%BD%AC%5DJava%20&%20PHP%20RSA%20%E4%BA%92%E9%80%9A%E5%AF%86%E9%92%A5%E3%80%81%E7%AD%BE%E5%90%8D%E3%80%81%E9%AA%8C%E7%AD%BE%E3%80%81%E5%8A%A0%E5%AF%86%E3%80%81%E8%A7%A3%E5%AF%86/">
[转]Java & PHP RSA 互通密钥、签名、验签、加密、解密
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<p>2020-06-07</p>
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<p>字数统计:</p>
<p>10字</p>
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<p>阅读时长≈</p>
<p>1分</p>
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<p>原文：<a href="https://www.cnblogs.com/bndong/p/11842135.html" target="_blank" rel="noopener">https://www.cnblogs.com/bndong/p/11842135.html</a></p>
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【LeetCode】192周赛-5428. 重新排列数组
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<p>字数统计:</p>
<p>278字</p>
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<p>阅读时长≈</p>
<p>1分</p>
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<p>题目来自【192场周赛】</p>
<h1 id="题目描述"><a href="#题目描述" class="headerlink" title="题目描述"></a>题目描述</h1><ol start="5428">
<li>重新排列数组 </li>
</ol>
<p>题目难度：Easy</p>
<p>给你一个数组 nums ，数组中有 2n 个元素，按 [x1,x2,…,xn,y1,y2,…,yn] 的格式排列。</p>
<p>请你将数组按 [x1,y1,x2,y2,…,xn,yn] 格式重新排列，返回重排后的数组。</p>
<p>示例 1：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line">输入：nums = [2,5,1,3,4,7], n = 3</span><br><span class="line">输出：[2,3,5,4,1,7] </span><br><span class="line">解释：由于 x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 ，所以答案为 [2,3,5,4,1,7]</span><br></pre></td></tr></table></figure>
<p>示例 2：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line">输入：nums = [1,2,3,4,4,3,2,1], n = 4</span><br><span class="line">输出：[1,4,2,3,3,2,4,1]</span><br></pre></td></tr></table></figure>
<p>示例 3：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line">输入：nums = [1,1,2,2], n = 2</span><br><span class="line">输出：[1,2,1,2]</span><br></pre></td></tr></table></figure>
<p>提示：</p>
<ul>
<li>1 <= n <= 500</li>
<li>nums.length == 2n</li>
<li>1 <= nums[i] <= 10^3</li>
</ul>
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【LeetCode】面试题29. 顺时针打印矩阵
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<p>2020-06-05</p>
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<p>字数统计:</p>
<p>745字</p>
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<p>阅读时长≈</p>
<p>4分</p>
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<h1 id="题目描述"><a href="#题目描述" class="headerlink" title="题目描述"></a>题目描述</h1><p>输入一个矩阵，按照从外向里以顺时针的顺序依次打印出每一个数字。</p>
<p>示例 1：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line">输入：matrix = [[1,2,3],[4,5,6],[7,8,9]]</span><br><span class="line">输出：[1,2,3,6,9,8,7,4,5]</span><br></pre></td></tr></table></figure>
<p>示例 2：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line">输入：matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]</span><br><span class="line">输出：[1,2,3,4,8,12,11,10,9,5,6,7]</span><br></pre></td></tr></table></figure>
<p>限制：</p>
<ul>
<li>0 <= matrix.length <= 100</li>
<li>0 <= matrix[i].length <= 100<br>注意：本题与主站 54 题相同：<a href="https://leetcode-cn.com/problems/spiral-matrix/" target="_blank" rel="noopener">54. 螺旋矩阵</a></li>
</ul>
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[转]什么是动态规划（Dynamic Programming）？动态规划的意义是什么？
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<p>字数统计:</p>
<p>24字</p>
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<p>1分</p>
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<p><a href="https://www.zhihu.com/question/23995189" target="_blank" rel="noopener">什么是动态规划（Dynamic Programming）？动态规划的意义是什么？</a><a href="https://github.com/melodyjerry/GitHub520" target="_blank" rel="noopener">https://github.com/melodyjerry/GitHub520</a>)</p>
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<a href="/blog/2020/06/02/%E6%8F%90%E9%AB%98GitHub%E7%9A%84%E8%AE%BF%E9%97%AE%E9%80%9F%E5%BA%A6(DNS%E5%AE%9E%E7%8E%B0)/">
提高GitHub的访问速度(DNS实现)
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<p>字数统计:</p>
<p>166字</p>
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<p>阅读时长≈</p>
<p>1分</p>
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<p>通过修改Hosts，文件路径<code>C:\Windows\System32\drivers\etc\hosts</code></p>
<blockquote>
<p>Linux 系统：/etc/hosts<br>Android（安卓）系统：/system/etc/hosts</p>
</blockquote>
<p>复制、粘贴：</p>
<figure class="highlight bash"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br></pre></td><td class="code"><pre><span class="line"><span class="comment"># GitHub520 Host Start</span></span><br><span class="line">185.199.108.154 github.githubassets.com</span><br><span class="line">199.232.68.133 camo.githubusercontent.com</span><br><span class="line">199.232.68.133 github.map.fastly.net</span><br><span class="line">199.232.69.194 github.global.ssl.fastly.net</span><br><span class="line">140.82.112.3 github.com</span><br><span class="line">140.82.114.5 api.github.com</span><br><span class="line">199.232.68.133 raw.githubusercontent.com</span><br><span class="line">199.232.68.133 favicons.githubusercontent.com</span><br><span class="line">199.232.68.133 avatars5.githubusercontent.com</span><br><span class="line">199.232.68.133 avatars4.githubusercontent.com</span><br><span class="line">199.232.68.133 avatars3.githubusercontent.com</span><br><span class="line">199.232.68.133 avatars2.githubusercontent.com</span><br><span class="line">199.232.68.133 avatars1.githubusercontent.com</span><br><span class="line">199.232.68.133 avatars0.githubusercontent.com</span><br><span class="line"><span class="comment"># GitHub520 Host End</span></span><br></pre></td></tr></table></figure>
<p>一般是立刻生效。<br>没有的话，手动在 CMD 敲入：<code>ipconfig /flushdns</code></p>
<h1 id="更多"><a href="#更多" class="headerlink" title="更多"></a>更多</h1><p>前往GitHub<a href="https://github.com/melodyjerry/GitHub520" target="_blank" rel="noopener">让你“爱”上 GitHub，解决访问时图裂、加载慢的问题。</a></p>
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<a href="/blog/2020/06/02/%5B%E8%BD%AC%5D%E5%89%91%E6%8C%87offer%E7%AC%AC%E4%BA%8C%E7%89%88%E6%80%BB%E7%BB%93%E2%80%94%E2%80%94%E5%9F%BA%E4%BA%8E%E7%89%9B%E5%AE%A2%E7%BD%91/">
[转]剑指offer第二版总结——基于牛客网
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<p>字数统计:</p>
<p>11.4k字</p>
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<p>阅读时长≈</p>
<p>56分</p>
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<a href="/blog/2020/06/02/%E3%80%90LeetCode%E3%80%91%E9%9D%A2%E8%AF%95%E9%A2%9864.%20%E6%B1%821+2+%E2%80%A6+n/">
【LeetCode】面试题64. 求1+2+…+n
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<p>字数统计:</p>
<p>806字</p>
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<p>阅读时长≈</p>
<p>4分</p>
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<p>来自<a href="https://www.jianshu.com/p/62cf4055617d" target="_blank" rel="noopener">《剑指Offer（第二版）》</a></p>
<h1 id="题目描述"><a href="#题目描述" class="headerlink" title="题目描述"></a>题目描述</h1><p>求 1+2+…+n ，要求<strong>不能使用<em>乘除法</em>、<code>for</code>、<code>while</code>、<code>if</code>、<code>else</code>、<code>switch</code>、<code>case</code>等关键字及<em>条件判断语句</em>（<code>A?B:C</code>）。</strong></p>
<p>示例 1：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line">输入: n = 3</span><br><span class="line">输出: 6</span><br></pre></td></tr></table></figure>
<p>示例 2：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line">输入: n = 9</span><br><span class="line">输出: 45</span><br></pre></td></tr></table></figure>
<p>限制：</p>
<ul>
<li>1 <= n <= 10000</li>
</ul>
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使用云函数自动完成网易云每日打卡
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<p>字数统计:</p>
<p>972字</p>
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<p>5分</p>
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【LeetCode】1431. 拥有最多糖果的孩子
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<p>字数统计:</p>
<p>636字</p>
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<p>2分</p>
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<p>首先祝Jerry生日快乐！<br><img src="https://img2020.cnblogs.com/blog/2013579/202006/2013579-20200601144625133-1492316422.png" alt=""></p>
<p>今天这个打卡题是关于“糖果”的，恰好六一儿童节。<br><img src="https://img2020.cnblogs.com/blog/2013579/202006/2013579-20200601144837678-528807032.png" alt=""></p>
<h1 id="题目描述"><a href="#题目描述" class="headerlink" title="题目描述"></a>题目描述</h1><p>给你一个数组 <code>candies</code> 和一个整数 <code>extraCandies</code> ，其中 <code>candies[i]</code> 代表第 <code>i</code> 个孩子拥有的糖果数目。</p>
<p>对每一个孩子，检查是否存在一种方案，将额外的 <code>extraCandies</code> 个糖果分配给孩子们之后，此孩子有 最多 的糖果。</p>
<p><strong>注意，允许有多个孩子同时拥有 最多 的糖果数目。</strong></p>
<p>示例 1：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br></pre></td><td class="code"><pre><span class="line">输入：candies = [2,3,5,1,3], extraCandies = 3</span><br><span class="line">输出：[true,true,true,false,true] </span><br><span class="line">解释：</span><br><span class="line">孩子 1 有 2 个糖果，如果他得到所有额外的糖果（3个），那么他总共有 5 个糖果，他将成为拥有最多糖果的孩子。</span><br><span class="line">孩子 2 有 3 个糖果，如果他得到至少 2 个额外糖果，那么他将成为拥有最多糖果的孩子。</span><br><span class="line">孩子 3 有 5 个糖果，他已经是拥有最多糖果的孩子。</span><br><span class="line">孩子 4 有 1 个糖果，即使他得到所有额外的糖果，他也只有 4 个糖果，无法成为拥有糖果最多的孩子。</span><br><span class="line">孩子 5 有 3 个糖果，如果他得到至少 2 个额外糖果，那么他将成为拥有最多糖果的孩子。</span><br></pre></td></tr></table></figure>
<p>示例 2：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line">输入：candies = [4,2,1,1,2], extraCandies = 1</span><br><span class="line">输出：[true,false,false,false,false] </span><br><span class="line">解释：只有 1 个额外糖果，所以不管额外糖果给谁，只有孩子 1 可以成为拥有糖果最多的孩子。</span><br></pre></td></tr></table></figure>
<p>示例 3：</p>
<figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line">输入：candies = [12,1,12], extraCandies = 10</span><br><span class="line">输出：[true,false,true]</span><br></pre></td></tr></table></figure>
<p>提示：</p>
<ul>
<li>2 <= candies.length <= 100</li>
<li>1 <= candies[i] <= 100</li>
<li>1 <= extraCandies <= 50</li>
</ul>
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});
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<script src="https://cdn.jsdelivr.net/gh/xaoxuu/cdn-material-x@19.11/js/app.js"></script>
<script src="https://cdn.jsdelivr.net/gh/xaoxuu/cdn-material-x@19.11/js/search.js"></script>
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<script src="https://cdn.jsdelivr.net/npm/clipboard@2/dist/clipboard.min.js"></script>
<script>
let COPY_SUCCESS = "复制成功";
let COPY_FAILURE = "复制失败";
/*页面载入完成后，创建复制按钮*/
!function (e, t, a) {
/* code */
var initCopyCode = function(){
var copyHtml = '';
copyHtml += '<button class="btn-copy" data-clipboard-snippet="">';
copyHtml += ' <i class="fa fa-copy"></i><span>复制</span>';
copyHtml += '</button>';
$(".highlight .code pre").before(copyHtml);
var clipboard = new ClipboardJS('.btn-copy', {
target: function(trigger) {
return trigger.nextElementSibling;
}
});
clipboard.on('success', function(e) {
//您可以加入成功提示
console.info('Action:', e.action);
console.info('Text:', e.text);
console.info('Trigger:', e.trigger);
success_prompt(COPY_SUCCESS);
e.clearSelection();
});
clipboard.on('error', function(e) {
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console.error('Action:', e.action);
console.error('Trigger:', e.trigger);
fail_prompt(COPY_FAILURE);
});
}
initCopyCode();
}(window, document);
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* 弹出式提示框，默认1.5秒自动消失
* @param message 提示信息
* @param style 提示样式，有alert-success、alert-danger、alert-warning、alert-info
* @param time 消失时间
*/
var prompt = function (message, style, time)
{
style = (style === undefined) ? 'alert-success' : style;
time = (time === undefined) ? 1500 : time*1000;
$('<div>')
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.addClass('alert ' + style)
.html(message)
.show()
.delay(time)
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};
// 成功提示
var success_prompt = function(message, time)
{
prompt(message, 'alert-success', time);
};
// 失败提示
var fail_prompt = function(message, time)
{
prompt(message, 'alert-danger', time);
};
// 提醒
var warning_prompt = function(message, time)
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prompt(message, 'alert-warning', time);
};
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{
prompt(message, 'alert-info', time);
};
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<script>
let LAZY_LOAD_IMAGE = "";
$(".article-entry").find("fancybox").find("img").each(function () {
var element = document.createElement("a");
$(element).attr("data-fancybox", "gallery");
$(element).attr("href", $(this).attr("src"));
/* 图片采用懒加载处理时,
* 一般图片标签内会有个属性名来存放图片的真实地址，比如 data-original,
* 那么此处将原本的属性名src替换为对应属性名data-original,
* 修改如下
*/
if (LAZY_LOAD_IMAGE) {
$(element).attr("href", $(this).attr("data-original"));
}
$(this).wrap(element);
});
</script>
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<script>setLoadingBarProgress(100);</script>
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<script type="text/javascript"
color="255,0,0" opacity='1' zIndex="-2" count="150" src="//cdn.bootcss.com/canvas-nest.js/1.0.0/canvas-nest.min.js">
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<script>
(function(a,h,g,f,e,d,c,b){b=function(){d=h.createElement(g);c=h.getElementsByTagName(g)[0];d.src=e;d.charset="utf-8";d.async=1;c.parentNode.insertBefore(d,c)};a["SeniverseWeatherWidgetObject"]=f;a[f]||(a[f]=function(){(a[f].q=a[f].q||[]).push(arguments)});a[f].l=+new Date();if(a.attachEvent){a.attachEvent("onload",b)}else{a.addEventListener("load",b,false)}}(window,document,"script","SeniverseWeatherWidget","//cdn.sencdn.com/widget2/static/js/bundle.js?t="+parseInt((new Date().getTime() / 100000000).toString(),10)));
window.SeniverseWeatherWidget('show', {
flavor: "bubble",
location: "WS0E9D8WN298",
geolocation: true,
language: "zh-Hans",
unit: "c",
theme: "auto",
token: "5fd5b254-57fe-4f8a-8a13-f92485efeb0b",
hover: "enabled",
container: "tp-weather-widget"
})
</script>
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<script src="https://cdn.jsdelivr.net/npm/typed.js@2.0.11"></script>
<script>var typed = new Typed("#subtitle", { strings: ["Live a good life, write some good code !!!", "愿自己的努力终将获得回报。", "花开不是为了花落，而是为了开的更加灿烂。", "没有伞的孩子必须努力奔跑！", "欲望以提升热忱，毅力以磨平高山。", "如果放弃太早，你永远都不知道自己会错过什么。", "没有礁石，就没有美丽的浪花；没有挫折，就没有壮丽的人生。"], startDelay: 1000, typeSpeed: 100, loop: !0, backSpeed: 60, backDelay: 2000, showCursor: !0 })</script>
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<script src="https://cdn.jsdelivr.net/npm/aplayer@1.10/dist/APlayer.min.js"></script>
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<script src="https://cdn.jsdelivr.net/gh/TRHX/CDN-for-itrhx.com@2.0.6/js/instantclick-1.2.2.js" type="module"></script>
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<script id="ilt" src="https://player.ilt.me/player/js/player.js" key="992f0d81b6b74b93b6bbdb56f57a6c58"></script>
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