一、漏洞信息
漏洞编号:CVE-2023-0179
漏洞归属组件:kernel
漏洞归属的版本:4.19.140,4.19.194,4.19.90,5.10.0,6.1.0,6.1.5,6.1.6
CVSS V2.0分值:
BaseScore:0.0 Low
Vector:CVSS:2.0/
漏洞简述:
A buffer overflow vulnerability was found in the Netfilter subsystem in the Linux Kernel. This issue could allow the leakage of both stack and heap addresses, and potentially allow Local Privilege Escalation to the root user via arbitrary code execution.
漏洞公开时间:
漏洞创建时间:2023-01-16 11:43:49
漏洞详情参考链接:
https://nvd.nist.gov/vuln/detail/CVE-2023-0179
漏洞分析指导链接:
https://gitee.com/openeuler/cve-manager/blob/master/cve-vulner-manager/doc/md/manual.md
漏洞数据来源:
openBrain开源漏洞感知系统
漏洞补丁信息:
无
二、漏洞分析结构反馈
影响性分析说明:
A buffer overflow vulnerability was found in the Netfilter subsystem in the Linux Kernel. This issue could allow the leakage of both stack and heap addresses, and potentially allow Local Privilege Escalation to the root user via arbitrary code execution.
openEuler评分:
7.8
Vector:CVSS:2.0/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:H/A:H
受影响版本排查(受影响/不受影响):
1.openEuler-22.03-LTS:受影响
2.openEuler-22.03-LTS-SP1:受影响
3.openEuler-20.03-LTS-SP1(4.19.90):不受影响
4.openEuler-20.03-LTS-SP3(4.19.90):不受影响
修复是否涉及abi变化(是/否):
1.openEuler-22.03-LTS:否
2.openEuler-20.03-LTS-SP1(4.19.90):否
3.openEuler-20.03-LTS-SP3(4.19.90):否
4.openEuler-22.03-LTS-SP1:否
三、漏洞修复
安全公告链接:https://www.openeuler.org/zh/security/safety-bulletin/detail/?id=openEuler-SA-2023-1072
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CVE-2023-0179
I6AOP8
影响性分析说明:
A buffer overflow vulnerability was found in the Netfilter subsystem in the Linux Kernel. This issue could allow the leakage of both stack and heap addresses, and potentially allow Local Privilege Escalation to the root user via arbitrary code execution.
openEuler评分:(评分和向量)
7.8
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:H/A:H
受影响版本排查(受影响/不受影响):
1.openEuler-22.03-LTS(5.10.0):受影响
2.openEuler-20.03-LTS-SP1(4.19.90):不受影响
3.openEuler-20.03-LTS-SP3(4.19.194):不受影响
4.openEuler-22.03-LTS-SP1:受影响
修复是否涉及abi变化(是/否):
1.openEuler-22.03-LTS(5.10.0):否
2.openEuler-20.03-LTS-SP1(4.19.90):否
3.openEuler-20.03-LTS-SP3(4.19.194):否
4.openEuler-22.03-LTS-SP1:否
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