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一、漏洞信息
漏洞编号：CVE-2024-57878
漏洞归属组件：kernel
漏洞归属的版本：4.19.140,4.19.194,4.19.90,5.10.0,6.1.19,6.1.8,6.4.0,6.6.0
CVSS V3.0分值：
BaseScore：6.1 Medium
Vector：CVSS：3.0/AV:L/AC:L/PR:L/UI:N/S:U/C:L/I:N/A:H
漏洞简述：
In the Linux kernel, the following vulnerability has been resolved:arm64: ptrace: fix partial SETREGSET for NT_ARM_FPMRCurrently fpmr_set() doesn t initialize the temporary fpmr variable,and a SETREGSET call with a length of zero will leave thisuninitialized. Consequently an arbitrary value will be written back totarget->thread.uw.fpmr, potentially leaking up to 64 bits of memory fromthe kernel stack. The read is limited to a specific slot on the stack,and the issue does not provide a write mechanism.Fix this by initializing the temporary value before copying the regsetfrom userspace, as for other regsets (e.g. NT_PRSTATUS, NT_PRFPREG,NT_ARM_SYSTEM_CALL). In the case of a zero-length write, the existingcontents of FPMR will be retained.Before this patch:| # ./fpmr-test| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d| SETREGSET(nt=0x40e, len=8) wrote 8 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d|| Attempting to write NT_ARM_FPMR (zero length)| SETREGSET(nt=0x40e, len=0) wrote 0 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0xffff800083963d50After this patch:| # ./fpmr-test| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d| SETREGSET(nt=0x40e, len=8) wrote 8 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d|| Attempting to write NT_ARM_FPMR (zero length)| SETREGSET(nt=0x40e, len=0) wrote 0 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
漏洞公开时间：2025-01-11 23:15:08
漏洞创建时间：2025-01-22 16:31:36
漏洞详情参考链接：
https://nvd.nist.gov/vuln/detail/CVE-2024-57878
漏洞分析指导链接：
https://gitee.com/openeuler/cve-manager/blob/master/cve-vulner-manager/doc/md/manual.md
漏洞数据来源:
openBrain开源漏洞感知系统
漏洞补丁信息：
二、漏洞分析结构反馈
影响性分析说明：
In the Linux kernel, the following vulnerability has been resolved:arm64: ptrace: fix partial SETREGSET for NT_ARM_FPMRCurrently fpmr_set() doesn t initialize the temporary fpmr variable,and a SETREGSET call with a length of zero will leave thisuninitialized. Consequently an arbitrary value will be written back totarget->thread.uw.fpmr, potentially leaking up to 64 bits of memory fromthe kernel stack. The read is limited to a specific slot on the stack,and the issue does not provide a write mechanism.Fix this by initializing the temporary value before copying the regsetfrom userspace, as for other regsets (e.g. NT_PRSTATUS, NT_PRFPREG,NT_ARM_SYSTEM_CALL). In the case of a zero-length write, the existingcontents of FPMR will be retained.Before this patch:| # ./fpmr-test| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d| SETREGSET(nt=0x40e, len=8) wrote 8 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d|| Attempting to write NT_ARM_FPMR (zero length)| SETREGSET(nt=0x40e, len=0) wrote 0 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0xffff800083963d50After this patch:| # ./fpmr-test| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d| SETREGSET(nt=0x40e, len=8) wrote 8 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d|| Attempting to write NT_ARM_FPMR (zero length)| SETREGSET(nt=0x40e, len=0) wrote 0 bytes|| Attempting to read NT_ARM_FPMR::fpmr| GETREGSET(nt=0x40e, len=8) read 8 bytes| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
openEuler评分：
6.1
Vector：CVSS：3.0/AV:L/AC:L/PR:L/UI:N/S:U/C:L/I:N/A:H
受影响版本排查(受影响/不受影响)：
1.openEuler-20.03-LTS-SP4(4.19.90):不受影响
2.openEuler-22.03-LTS-SP3(5.10.0):不受影响
3.openEuler-22.03-LTS-SP4:不受影响
4.master(6.6.0):不受影响
5.openEuler-24.03-LTS:不受影响
6.openEuler-24.03-LTS-Next:不受影响
7.openEuler-24.03-LTS-SP1:不受影响
修复是否涉及abi变化(是/否)：
1.openEuler-20.03-LTS-SP4(4.19.90):否
2.openEuler-22.03-LTS-SP3(5.10.0):否
3.master(6.6.0):否
4.openEuler-24.03-LTS:否
5.openEuler-24.03-LTS-Next:否
6.openEuler-22.03-LTS-SP4:否
7.openEuler-24.03-LTS-SP1:否
原因说明：
1.master(6.6.0):不受影响-漏洞代码不能被攻击者触发
2.openEuler-24.03-LTS-Next:不受影响-漏洞代码不能被攻击者触发
3.openEuler-20.03-LTS-SP4(4.19.90):不受影响-漏洞代码不存在
4.openEuler-22.03-LTS-SP3(5.10.0):不受影响-漏洞代码不存在
5.openEuler-22.03-LTS-SP4:不受影响-漏洞代码不存在
6.openEuler-24.03-LTS:不受影响-漏洞代码不存在
7.openEuler-24.03-LTS-SP1:不受影响-漏洞代码不存在
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| 参考网址 | 关联pr | 状态 | 补丁链接 |
|---|---|---|---|
| https://nvd.nist.gov/vuln/detail/CVE-2024-57878 | None | None | https://git.kernel.org/stable/c/f5d71291841aecfe5d8435da2dfa7f58ccd18bc8 https://git.kernel.org/stable/c/8ab73c34e3c5b580721696665eabd799346bc50b |
| https://ubuntu.com/security/CVE-2024-57878 | None | None | https://git.kernel.org/stable/c/8ab73c34e3c5b580721696665eabd799346bc50b https://git.kernel.org/linus/4035c22ef7d43a6c00d6a6584c60e902b95b46af https://git.kernel.org/stable/c/f5d71291841aecfe5d8435da2dfa7f58ccd18bc8 https://git.kernel.org/linus/f5d71291841aecfe5d8435da2dfa7f58ccd18bc8 https://discourse.ubuntu.com/c/project |
| https://www.opencve.io/cve/CVE-2024-57878 | |||
| https://bugzilla.redhat.com/show_bug.cgi?id=CVE-2024-57878 | |||
| https://security-tracker.debian.org/tracker/CVE-2024-57878 |
说明：补丁链接仅供初步排查参考，实际可用性请人工再次确认，补丁下载验证可使用CVE补丁工具。
若补丁不准确，烦请在此issue下评论 '/report-patch 参考网址 补丁链接1,补丁链接2' 反馈正确信息，便于我们不断优化工具，不胜感激。
如 /report-patch https://security-tracker.debian.org/tracker/CVE-2021-3997 https://github.com/systemd/systemd/commit/5b1cf7a9be37e20133c0208005274ce4a5b5c6a1
hulk-robot
2个月前
CVE-2024-57878
影响性分析说明：
In the Linux kernel, the following vulnerability has been resolved:
arm64: ptrace: fix partial SETREGSET for NT_ARM_FPMR
Currently fpmr_set() doesn't initialize the temporary 'fpmr' variable,
and a SETREGSET call with a length of zero will leave this
uninitialized. Consequently an arbitrary value will be written back to
target->thread.uw.fpmr, potentially leaking up to 64 bits of memory from
the kernel stack. The read is limited to a specific slot on the stack,
and the issue does not provide a write mechanism.
Fix this by initializing the temporary value before copying the regset
from userspace, as for other regsets (e.g. NT_PRSTATUS, NT_PRFPREG,
NT_ARM_SYSTEM_CALL). In the case of a zero-length write, the existing
contents of FPMR will be retained.
Before this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0xffff800083963d50
After this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
The Linux kernel CVE team has assigned CVE-2024-57878 to this issue.
openEuler评分:(评分和向量)
6.1
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:L/I:N/A:H
受影响版本排查(受影响/不受影响):
1.master(6.1.0):不受影响
2.openEuler-20.03-LTS-SP4:不受影响
3.openEuler-22.03-LTS-SP3:不受影响
4.openEuler-22.03-LTS-SP4:不受影响
5.openEuler-24.03-LTS:不受影响
6.openEuler-24.03-LTS-Next:不受影响
7.openEuler-24.03-LTS-SP1:不受影响
修复是否涉及abi变化(是/否)：
1.master(6.1.0):否
2.openEuler-20.03-LTS-SP4:否
3.openEuler-22.03-LTS-SP3:否
4.openEuler-22.03-LTS-SP4:否
5.openEuler-24.03-LTS:否
6.openEuler-24.03-LTS-Next:否
7.openEuler-24.03-LTS-SP1:否
原因说明：
1.master(23.08.5):不受影响-漏洞代码不能被攻击者触发
2.openEuler-20.03-LTS-SP4:不受影响-漏洞代码不存在
4.openEuler-22.03-LTS-SP3:不受影响-漏洞代码不存在
5.openEuler-22.03-LTS-SP4:不受影响-漏洞代码不存在
6.openEuler-24.03-LTS:不受影响-漏洞代码不存在
7.openEuler-24.03-LTS-Next:不受影响-漏洞代码不能被攻击者触发
8.openEuler-24.03-LTS-SP1:不受影响-漏洞代码不存在
郭梦琪
2个月前
CVE-2024-57878
影响性分析说明：
In the Linux kernel, the following vulnerability has been resolved:
arm64: ptrace: fix partial SETREGSET for NT_ARM_FPMR
Currently fpmr_set() doesn't initialize the temporary 'fpmr' variable,
and a SETREGSET call with a length of zero will leave this
uninitialized. Consequently an arbitrary value will be written back to
target->thread.uw.fpmr, potentially leaking up to 64 bits of memory from
the kernel stack. The read is limited to a specific slot on the stack,
and the issue does not provide a write mechanism.
Fix this by initializing the temporary value before copying the regset
from userspace, as for other regsets (e.g. NT_PRSTATUS, NT_PRFPREG,
NT_ARM_SYSTEM_CALL). In the case of a zero-length write, the existing
contents of FPMR will be retained.
Before this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0xffff800083963d50
After this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
openEuler评分:(评分和向量)
6.1
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:L/I:N/A:H
受影响版本排查(受影响/不受影响):
1.openEuler-20.03-LTS-SP4:不受影响
2.openEuler-22.03-LTS-SP3:不受影响
3.openEuler-22.03-LTS-SP4:不受影响
4.master(6.6.0):不受影响
5.openEuler-24.03-LTS:不受影响
6.openEuler-24.03-LTS-Next:不受影响
7.openEuler-24.03-LTS-SP1:不受影响
原因说明:
1.openEuler-20.03-LTS-SP4:不受影响-漏洞代码不存在
2.openEuler-22.03-LTS-SP3:不受影响-漏洞代码不存在
3.openEuler-22.03-LTS-SP4:不受影响-漏洞代码不存在
4.master(6.6.0):不受影响-漏洞代码不能被攻击者触发
5.openEuler-24.03-LTS:不受影响-漏洞代码不存在
6.openEuler-24.03-LTS-Next:不受影响-漏洞代码不能被攻击者触发
7.openEuler-24.03-LTS-SP1:不受影响-漏洞代码不存在
修复是否涉及abi变化(是/否)：
1.openEuler-20.03-LTS-SP4:否
2.openEuler-22.03-LTS-SP3:否
3.master(23.08.5):否
4.openEuler-24.03-LTS:否
5.openEuler-24.03-LTS-Next:否
6.openEuler-22.03-LTS-SP4:否
7.openEuler-24.03-LTS-SP1:否
===========================================================
郭梦琪
2个月前
CVE-2024-57878
影响性分析说明：
In the Linux kernel, the following vulnerability has been resolved:
arm64: ptrace: fix partial SETREGSET for NT_ARM_FPMR
Currently fpmr_set() doesn't initialize the temporary 'fpmr' variable,
and a SETREGSET call with a length of zero will leave this
uninitialized. Consequently an arbitrary value will be written back to
target->thread.uw.fpmr, potentially leaking up to 64 bits of memory from
the kernel stack. The read is limited to a specific slot on the stack,
and the issue does not provide a write mechanism.
Fix this by initializing the temporary value before copying the regset
from userspace, as for other regsets (e.g. NT_PRSTATUS, NT_PRFPREG,
NT_ARM_SYSTEM_CALL). In the case of a zero-length write, the existing
contents of FPMR will be retained.
Before this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0xffff800083963d50
After this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
openEuler评分:(评分和向量)
6.1
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:L/I:N/A:H
受影响版本排查(受影响/不受影响):
1.openEuler-20.03-LTS-SP4:不受影响
2.openEuler-22.03-LTS-SP3:不受影响
3.openEuler-22.03-LTS-SP4:不受影响
4.master(6.6.0):不受影响
5.openEuler-24.03-LTS:不受影响
6.openEuler-24.03-LTS-Next:不受影响
7.openEuler-24.03-LTS-SP1:不受影响
原因说明:
1.openEuler-20.03-LTS-SP4:不受影响-漏洞代码不存在
2.openEuler-22.03-LTS-SP3:不受影响-漏洞代码不存在
3.openEuler-22.03-LTS-SP4:不受影响-漏洞代码不存在
4.master(6.6.0):不受影响-漏洞代码不能被攻击者触发
5.openEuler-24.03-LTS:不受影响-漏洞代码不存在
6.openEuler-24.03-LTS-Next:不受影响-漏洞代码不能被攻击者触发
7.openEuler-24.03-LTS-SP1:不受影响-漏洞代码不存在
修复是否涉及abi变化(是/否)：
1.openEuler-20.03-LTS-SP4:否
2.openEuler-22.03-LTS-SP3:否
3.master(23.08.5):否
4.openEuler-24.03-LTS:否
5.openEuler-24.03-LTS-Next:否
6.openEuler-22.03-LTS-SP4:否
7.openEuler-24.03-LTS-SP1:否
===========================================================
郭梦琪
2个月前
CVE-2024-57878
影响性分析说明：
In the Linux kernel, the following vulnerability has been resolved:
arm64: ptrace: fix partial SETREGSET for NT_ARM_FPMR
Currently fpmr_set() doesn't initialize the temporary 'fpmr' variable,
and a SETREGSET call with a length of zero will leave this
uninitialized. Consequently an arbitrary value will be written back to
target->thread.uw.fpmr, potentially leaking up to 64 bits of memory from
the kernel stack. The read is limited to a specific slot on the stack,
and the issue does not provide a write mechanism.
Fix this by initializing the temporary value before copying the regset
from userspace, as for other regsets (e.g. NT_PRSTATUS, NT_PRFPREG,
NT_ARM_SYSTEM_CALL). In the case of a zero-length write, the existing
contents of FPMR will be retained.
Before this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0xffff800083963d50
After this patch:
| # ./fpmr-test
| Attempting to write NT_ARM_FPMR::fpmr = 0x900d900d900d900d
| SETREGSET(nt=0x40e, len=8) wrote 8 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
|
| Attempting to write NT_ARM_FPMR (zero length)
| SETREGSET(nt=0x40e, len=0) wrote 0 bytes
|
| Attempting to read NT_ARM_FPMR::fpmr
| GETREGSET(nt=0x40e, len=8) read 8 bytes
| Read NT_ARM_FPMR::fpmr = 0x900d900d900d900d
openEuler评分:(评分和向量)
6.1
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:L/I:N/A:H
受影响版本排查(受影响/不受影响):
1.openEuler-20.03-LTS-SP4:不受影响
2.openEuler-22.03-LTS-SP3:不受影响
3.openEuler-22.03-LTS-SP4:不受影响
4.master(6.6.0):不受影响
5.openEuler-24.03-LTS:不受影响
6.openEuler-24.03-LTS-Next:不受影响
7.openEuler-24.03-LTS-SP1:不受影响
原因说明:
1.openEuler-20.03-LTS-SP4:不受影响-漏洞代码不存在
2.openEuler-22.03-LTS-SP3:不受影响-漏洞代码不存在
3.openEuler-22.03-LTS-SP4:不受影响-漏洞代码不存在
4.master(6.6.0):不受影响-漏洞代码不能被攻击者触发
5.openEuler-24.03-LTS:不受影响-漏洞代码不存在
6.openEuler-24.03-LTS-Next:不受影响-漏洞代码不能被攻击者触发
7.openEuler-24.03-LTS-SP1:不受影响-漏洞代码不存在
修复是否涉及abi变化(是/否)：
1.openEuler-20.03-LTS-SP4:否
2.openEuler-22.03-LTS-SP3:否
3.master(23.08.5):否
4.openEuler-24.03-LTS:否
5.openEuler-24.03-LTS-Next:否
6.openEuler-22.03-LTS-SP4:否
7.openEuler-24.03-LTS-SP1:否
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