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recursiveStaircaseMEM.js 1.35 KB
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Oleksii Trekhleb 提交于 2018-11-14 23:45 +08:00 . Add Recursive Staircase Problem.
/**
* Recursive Staircase Problem (Recursive Solution With Memoization).
*
* @param {number} totalStairs - Number of stairs to climb on.
* @return {number} - Number of ways to climb a staircase.
*/
export default function recursiveStaircaseMEM(totalStairs) {
// Memo table that will hold all recursively calculated results to avoid calculating them
// over and over again.
const memo = [];
// Recursive closure.
const getSteps = (stairsNum) => {
if (stairsNum <= 0) {
// There is no way to go down - you climb the stairs only upwards.
// Also if you're standing on the ground floor that you don't need to do any further steps.
return 0;
}
if (stairsNum === 1) {
// There is only one way to go to the first step.
return 1;
}
if (stairsNum === 2) {
// There are two ways to get to the second steps: (1 + 1) or (2).
return 2;
}
// Avoid recursion for the steps that we've calculated recently.
if (memo[stairsNum]) {
return memo[stairsNum];
}
// Sum up how many steps we need to take after doing one step up with the number of
// steps we need to take after doing two steps up.
memo[stairsNum] = getSteps(stairsNum - 1) + getSteps(stairsNum - 2);
return memo[stairsNum];
};
// Return possible ways to get to the requested step.
return getSteps(totalStairs);
}
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