Ai
2 Star 0 Fork 0

CS-IMIS-23/GK20172301_JavaProgramming

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
克隆/下载
ExpressionTree.java 3.82 KB
一键复制 编辑 原始数据 按行查看 历史
20172301郭恺 提交于 2018-10-29 18:42 +08:00 . 使用二叉树:表达式树
package week6;
import week4.ArrayUnorderedList;
import week4.UnorderedListADT;
public class ExpressionTree extends LinkedBinaryTree<ExpressionTreeOp>
{
// 创建一个空的表达式树
public ExpressionTree()
{
super();
}
// 从两个指定的表达式构造表达式树
public ExpressionTree(ExpressionTreeOp element,
ExpressionTree leftSubtree, ExpressionTree rightSubtree)
{
root = new BinaryTreeNode<ExpressionTreeOp>(element, leftSubtree, rightSubtree);
}
// 通过调用递归计算表达式树evaluateNode方法。
public int evaluateTree()
{
return evaluateNode(root);
}
// 递归地计算树的每个节点。
public int evaluateNode(BinaryTreeNode root)
{
int result, operand1, operand2;
ExpressionTreeOp temp;
if (root==null)
result = 0;
else
{
temp = (ExpressionTreeOp)root.getElement();
if (temp.isOperator())
{
operand1 = evaluateNode(root.getLeft());
operand2 = evaluateNode(root.getRight());
result = computeTerm(temp.getOperator(), operand1, operand2);
}
else
result = temp.getValue();
}
return result;
}
// 计算一个由运算符和两个操作数组成的术语。
private static int computeTerm(char operator, int operand1, int operand2)
{
int result=0;
if (operator == '+')
result = operand1 + operand2;
else if (operator == '-')
result = operand1 - operand2;
else if (operator == '*')
result = operand1 * operand2;
else
result = operand1 / operand2;
return result;
}
// 通过执行生成树的结构化字符串版本层次遍历。
public String printTree()
{
UnorderedListADT<BinaryTreeNode<ExpressionTreeOp>> nodes =
new ArrayUnorderedList<BinaryTreeNode<ExpressionTreeOp>>();
UnorderedListADT<Integer> levelList =
new ArrayUnorderedList<Integer>();
BinaryTreeNode<ExpressionTreeOp> current;
String result = "";
int printDepth = this.getHeight();
int possibleNodes = (int)Math.pow(2, printDepth + 1); // 最多的结点数 + 1
int countNodes = 0;
nodes.addToRear(root);
Integer currentLevel = 0;
Integer previousLevel = -1;
levelList.addToRear(currentLevel);
while (countNodes < possibleNodes)
{
countNodes = countNodes + 1;
current = nodes.removeFirst();
currentLevel = levelList.removeFirst();
if (currentLevel > previousLevel)
{
result = result + "\n\n";
previousLevel = currentLevel;
for (int j = 0; j < ((Math.pow(2, (printDepth - currentLevel))) - 1); j++)
result = result + " ";
}
else
{
for (int i = 0; i < ((Math.pow(2, (printDepth - currentLevel + 1)) - 1)) ; i++)
{
result = result + " ";
}
}
if (current != null)
{
result = result + (current.getElement()).toString();
nodes.addToRear(current.getLeft());
levelList.addToRear(currentLevel + 1);
nodes.addToRear(current.getRight());
levelList.addToRear(currentLevel + 1);
}
else {
nodes.addToRear(null);
levelList.addToRear(currentLevel + 1);
nodes.addToRear(null);
levelList.addToRear(currentLevel + 1);
result = result + " ";
}
}
return result;
}
}
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
Java
1
https://gitee.com/CS-IMIS-23/GK20172301_JavaProgramming.git
git@gitee.com:CS-IMIS-23/GK20172301_JavaProgramming.git
CS-IMIS-23
GK20172301_JavaProgramming
GK20172301_JavaProgramming
master

搜索帮助