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intersection-of-two-linked-lists.cpp 1.00 KB
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kamyu 提交于 2016-03-17 21:37 +08:00 . Create intersection-of-two-linked-lists.cpp
// Time: O(m + n)
// Space: O(1)
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *getIntersectionNode(ListNode *headA, ListNode *headB) {
ListNode *curA = headA, *curB = headB;
ListNode *begin = nullptr, *tailA = nullptr, *tailB = nullptr;
while (curA && curB) {
if (curA == curB) {
begin = curA;
break;
}
if (curA->next) {
curA = curA->next;
} else if (!tailA) {
tailA = curA;
curA = headB;
} else {
break;
}
if (curB->next) {
curB = curB->next;
} else if (!tailB) {
tailB = curB;
curB = headA;
} else {
break;
}
}
return begin;
}
};
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