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maximum-sum-of-two-non-overlapping-subarrays.cpp 619 Bytes
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// Time: O(n)
// Space: O(1)
class Solution {
public:
int maxSumTwoNoOverlap(vector<int>& A, int L, int M) {
for (int i = 1; i < A.size(); ++i) {
A[i] += A[i - 1];
}
int result = A[L + M - 1], L_max = A[L - 1], M_max = A[M - 1];
for (int i = L + M; i < A.size(); ++i) {
L_max = max(L_max, A[i - M] - A[i - L - M]);
M_max = max(M_max, A[i - L] - A[i - L - M]);
result = max(result,
max(L_max + A[i] - A[i - M],
M_max + A[i] - A[i - L]));
}
return result;
}
};
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