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wiggle-sort-ii.cpp 3.30 KB
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kamyu 提交于 9年前 . Update wiggle-sort-ii.cpp
// Time: O(n) ~ O(n^2), O(n) on average.
// Space: O(1)
// Tri Partition (aka Dutch National Flag Problem) with virtual index solution. (44ms)
class Solution {
public:
void wiggleSort(vector<int>& nums) {
int mid = (nums.size() - 1) / 2;
nth_element(nums.begin(), nums.begin() + mid, nums.end()); // O(n) ~ O(n^2) time
reversedTriPartitionWithVI(nums, nums[mid]); // O(n) time, O(1) space
}
void reversedTriPartitionWithVI(vector<int>& nums, int val) {
const int N = nums.size() / 2 * 2 + 1;
#define Nums(i) nums[(1 + 2 * (i)) % N]
for (int i = 0, j = 0, n = nums.size() - 1; j <= n;) {
if (Nums(j) > val) {
swap(Nums(i++), Nums(j++));
} else if (Nums(j) < val) {
swap(Nums(j), Nums(n--));
} else {
++j;
}
}
}
};
// Time: O(n) ~ O(n^2)
// Space: O(n)
// Tri Partition (aka Dutch National Flag Problem) solution. (64ms)
class Solution2 {
public:
void wiggleSort(vector<int>& nums) {
int mid = (nums.size() - 1) / 2;
nth_element(nums.begin(), nums.begin() + mid, nums.end()); // O(n) ~ O(n^2) time
triPartition(nums, nums[mid]); // O(n) time, O(1) space
vector<int> res(nums.size()); // O(n) space
for (int i = 0, smallEnd = mid; i < nums.size(); i += 2, --smallEnd) {
res[i] = nums[smallEnd];
}
for (int i = 1, largeEnd = nums.size() - 1; i < nums.size(); i += 2, --largeEnd) {
res[i] = nums[largeEnd];
}
nums = res;
}
void triPartition(vector<int>& nums, int val) {
for (int i = 0, j = 0, n = nums.size() - 1; j <= n;) {
if (nums[j] < val) {
swap(nums[i++], nums[j++]);
} else if (nums[j] > val) {
swap(nums[j], nums[n--]);
} else {
++j;
}
}
}
};
// Time: O(nlogn)
// Space: O(1)
// Sorting and Tri Partition (aka Dutch National Flag Problem) with virtual index solution. (64ms)
class Solution3 {
public:
void wiggleSort(vector<int>& nums) {
int mid = (nums.size() - 1) / 2;
sort(nums.begin(), nums.end()); // O(nlogn) time
reversedTriPartitionWithVI(nums, nums[mid]); // O(n) time, O(1) space
}
void reversedTriPartitionWithVI(vector<int>& nums, int val) {
const int N = nums.size() / 2 * 2 + 1;
#define Nums(i) nums[(1 + 2 * (i)) % N]
for (int i = 0, j = 0, n = nums.size() - 1; j <= n;) {
if (Nums(j) > val) {
swap(Nums(i++), Nums(j++));
} else if (Nums(j) < val) {
swap(Nums(j), Nums(n--));
} else {
++j;
}
}
}
};
// Time: O(nlogn)
// Space: O(n)
// Sorting and reorder solution. (64ms)
class Solution4 {
public:
void wiggleSort(vector<int>& nums) {
int mid = (nums.size() - 1) / 2;
sort(nums.begin(), nums.end()); // O(nlogn) time
vector<int> res(nums.size()); // O(n) space
for (int i = 0, smallEnd = mid; i < nums.size(); i += 2, --smallEnd) {
res[i] = nums[smallEnd];
}
for (int i = 1, largeEnd = nums.size() - 1; i < nums.size(); i += 2, --largeEnd) {
res[i] = nums[largeEnd];
}
nums = res;
}
};
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