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brick-wall.py 579 Bytes
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Allen Liu 提交于 2018-10-13 13:15 +08:00 . remove unused code
# Time: O(n), n is the total number of the bricks
# Space: O(m), m is the total number different widths
import collections
class Solution(object):
def leastBricks(self, wall):
"""
:type wall: List[List[int]]
:rtype: int
"""
widths = collections.defaultdict(int)
result = len(wall)
for row in wall:
width = 0
for i in xrange(len(row)-1):
width += row[i]
widths[width] += 1
result = min(result, len(wall) - widths[width])
return result
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