Ai
1 Star 2 Fork 5

LilithSangreal/LeetCode-Solutions

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
克隆/下载
continuous-subarray-sum.py 523 Bytes
一键复制 编辑 原始数据 按行查看 历史
Allen Liu 提交于 2018-10-12 01:33 +08:00 . remove sensitive question description
# Time: O(n)
# Space: O(k)
class Solution(object):
def checkSubarraySum(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: bool
"""
count = 0
lookup = {0: -1}
for i, num in enumerate(nums):
count += num
if k:
count %= k
if count in lookup:
if i - lookup[count] > 1:
return True
else:
lookup[count] = i
return False
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
1
https://gitee.com/LilithSangreal/LeetCode-Solutions.git
git@gitee.com:LilithSangreal/LeetCode-Solutions.git
LilithSangreal
LeetCode-Solutions
LeetCode-Solutions
master

搜索帮助