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count-univalue-subtrees.py 760 Bytes
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Allen Liu 提交于 2018-12-30 21:04 +08:00 . remove semicolons
# Time: O(n)
# Space: O(h)
class Solution(object):
# @param {TreeNode} root
# @return {integer}
def countUnivalSubtrees(self, root):
[is_uni, count] = self.isUnivalSubtrees(root, 0)
return count
def isUnivalSubtrees(self, root, count):
if not root:
return [True, count]
[left, count] = self.isUnivalSubtrees(root.left, count)
[right, count] = self.isUnivalSubtrees(root.right, count)
if self.isSame(root, root.left, left) and \
self.isSame(root, root.right, right):
count += 1
return [True, count]
return [False, count]
def isSame(self, root, child, is_uni):
return not child or (is_uni and root.val == child.val)
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