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delete-node-in-a-linked-list.py 377 Bytes
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Allen Liu 提交于 2018-10-13 13:24 +08:00 . update
# Time: O(1)
# Space: O(1)
class Solution(object):
# @param {ListNode} node
# @return {void} Do not return anything, modify node in-place instead.
def deleteNode(self, node):
if node and node.next:
node_to_delete = node.next
node.val = node_to_delete.val
node.next = node_to_delete.next
del node_to_delete
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