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diameter-of-binary-tree.py 483 Bytes
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Allen Liu 提交于 2018-10-13 01:56 +08:00 . add complexity
# Time: O(n)
# Space: O(h)
class Solution(object):
def diameterOfBinaryTree(self, root):
"""
:type root: TreeNode
:rtype: int
"""
return self.depth(root, 0)[1]
def depth(self, root, diameter):
if not root:
return 0, diameter
left, diameter = self.depth(root.left, diameter)
right, diameter = self.depth(root.right, diameter)
return 1 + max(left, right), max(diameter, left + right)
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