代码拉取完成,页面将自动刷新
# Time: O(n)
# Space: O(h)
class Solution(object):
# @param {TreeNode} root
# @param {TreeNode} p
# @param {TreeNode} q
# @return {TreeNode}
def lowestCommonAncestor(self, root, p, q):
if root in (None, p, q):
return root
left, right = [self.lowestCommonAncestor(child, p, q) \
for child in (root.left, root.right)]
# 1. If the current subtree contains both p and q,
# return their LCA.
# 2. If only one of them is in that subtree,
# return that one of them.
# 3. If neither of them is in that subtree,
# return the node of that subtree.
return root if left and right else left or right
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。