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maximum-product-of-three-numbers.py 741 Bytes
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Allen Liu 提交于 2018-10-12 01:33 +08:00 . remove sensitive question description
# Time: O(n)
# Space: O(1)
class Solution(object):
def maximumProduct(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
min1, min2 = float("inf"), float("inf")
max1, max2, max3 = float("-inf"), float("-inf"), float("-inf")
for n in nums:
if n <= min1:
min2 = min1
min1 = n
elif n <= min2:
min2 = n
if n >= max1:
max3 = max2
max2 = max1
max1 = n
elif n >= max2:
max3 = max2
max2 = n
elif n >= max3:
max3 = n
return max(min1 * min2 * max1, max1 * max2 * max3)
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