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merge-k-sorted-lists.py 2.70 KB
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Allen Liu 提交于 2018-12-30 21:04 +08:00 . remove semicolons
# Time: O(nlogk)
# Space: O(1)
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
def __repr__(self):
if self:
return "{} -> {}".format(self.val, self.next)
# Merge two by two solution.
class Solution(object):
def mergeKLists(self, lists):
"""
:type lists: List[ListNode]
:rtype: ListNode
"""
def mergeTwoLists(l1, l2):
curr = dummy = ListNode(0)
while l1 and l2:
if l1.val < l2.val:
curr.next = l1
l1 = l1.next
else:
curr.next = l2
l2 = l2.next
curr = curr.next
curr.next = l1 or l2
return dummy.next
if not lists:
return None
left, right = 0, len(lists) - 1
while right > 0:
if left >= right:
left = 0
else:
lists[left] = mergeTwoLists(lists[left], lists[right])
left += 1
right -= 1
return lists[0]
# Time: O(nlogk)
# Space: O(logk)
# Divide and Conquer solution.
class Solution2(object):
# @param a list of ListNode
# @return a ListNode
def mergeKLists(self, lists):
def mergeTwoLists(l1, l2):
curr = dummy = ListNode(0)
while l1 and l2:
if l1.val < l2.val:
curr.next = l1
l1 = l1.next
else:
curr.next = l2
l2 = l2.next
curr = curr.next
curr.next = l1 or l2
return dummy.next
def mergeKListsHelper(lists, begin, end):
if begin > end:
return None
if begin == end:
return lists[begin]
return mergeTwoLists(mergeKListsHelper(lists, begin, (begin + end) / 2), \
mergeKListsHelper(lists, (begin + end) / 2 + 1, end))
return mergeKListsHelper(lists, 0, len(lists) - 1)
# Time: O(nlogk)
# Space: O(k)
# Heap solution.
import heapq
class Solution3(object):
# @param a list of ListNode
# @return a ListNode
def mergeKLists(self, lists):
dummy = ListNode(0)
current = dummy
heap = []
for sorted_list in lists:
if sorted_list:
heapq.heappush(heap, (sorted_list.val, sorted_list))
while heap:
smallest = heapq.heappop(heap)[1]
current.next = smallest
current = current.next
if smallest.next:
heapq.heappush(heap, (smallest.next.val, smallest.next))
return dummy.next
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