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palindrome-linked-list.py 898 Bytes
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Allen Liu 提交于 2018-10-13 13:24 +08:00 . update
# Time: O(n)
# Space: O(1)
class Solution(object):
# @param {ListNode} head
# @return {boolean}
def isPalindrome(self, head):
reverse, fast = None, head
# Reverse the first half part of the list.
while fast and fast.next:
fast = fast.next.next
head.next, reverse, head = reverse, head, head.next
# If the number of the nodes is odd,
# set the head of the tail list to the next of the median node.
tail = head.next if fast else head
# Compare the reversed first half list with the second half list.
# And restore the reversed first half list.
is_palindrome = True
while reverse:
is_palindrome = is_palindrome and reverse.val == tail.val
reverse.next, head, reverse = head, reverse, reverse.next
tail = tail.next
return is_palindrome
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