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populating-next-right-pointers-in-each-node-ii.py 1.07 KB
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Allen Liu 提交于 7年前 . update
# Time: O(n)
# Space: O(1)
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
self.next = None
def __repr__(self):
if self is None:
return "Nil"
else:
return "{} -> {}".format(self.val, repr(self.next))
class Solution(object):
# @param root, a tree node
# @return nothing
def connect(self, root):
head = root
while head:
prev, cur, next_head = None, head, None
while cur:
if next_head is None:
if cur.left:
next_head = cur.left
elif cur.right:
next_head = cur.right
if cur.left:
if prev:
prev.next = cur.left
prev = cur.left
if cur.right:
if prev:
prev.next = cur.right
prev = cur.right
cur = cur.next
head = next_head
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