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scramble-string.py 952 Bytes
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Allen Liu 提交于 2018-10-13 13:24 +08:00 . update
# Time: O(n^4)
# Space: O(n^3)
class Solution(object):
# @return a boolean
def isScramble(self, s1, s2):
if not s1 or not s2 or len(s1) != len(s2):
return False
if s1 == s2:
return True
result = [[[False for j in xrange(len(s2))] for i in xrange(len(s1))] for n in xrange(len(s1) + 1)]
for i in xrange(len(s1)):
for j in xrange(len(s2)):
if s1[i] == s2[j]:
result[1][i][j] = True
for n in xrange(2, len(s1) + 1):
for i in xrange(len(s1) - n + 1):
for j in xrange(len(s2) - n + 1):
for k in xrange(1, n):
if result[k][i][j] and result[n - k][i + k][j + k] or\
result[k][i][j + n - k] and result[n - k][i + k][j]:
result[n][i][j] = True
break
return result[n][0][0]
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