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single-number-iii.py 964 Bytes
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Allen Liu 提交于 2018-10-13 13:24 +08:00 . update
# Time: O(n)
# Space: O(1)
import operator
import collections
class Solution(object):
# @param {integer[]} nums
# @return {integer[]}
def singleNumber(self, nums):
x_xor_y = reduce(operator.xor, nums)
bit = x_xor_y & -x_xor_y
result = [0, 0]
for i in nums:
result[bool(i & bit)] ^= i
return result
class Solution2(object):
# @param {integer[]} nums
# @return {integer[]}
def singleNumber(self, nums):
x_xor_y = 0
for i in nums:
x_xor_y ^= i
bit = x_xor_y & ~(x_xor_y - 1)
x = 0
for i in nums:
if i & bit:
x ^= i
return [x, x ^ x_xor_y]
class Solution3(object):
def singleNumber(self, nums):
"""
:type nums: List[int]
:rtype: List[int]
"""
return [x[0] for x in sorted(collections.Counter(nums).items(), key=lambda i: i[1], reverse=False)[:2]]
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