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strobogrammatic-number-ii.py 657 Bytes
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Allen Liu 提交于 2018-10-13 13:24 +08:00 . update
# Time: O(n^2 * 5^(n/2))
# Space: O(n)
class Solution(object):
lookup = {'0':'0', '1':'1', '6':'9', '8':'8', '9':'6'}
# @param {integer} n
# @return {string[]}
def findStrobogrammatic(self, n):
return self.findStrobogrammaticRecu(n, n)
def findStrobogrammaticRecu(self, n, k):
if k == 0:
return ['']
elif k == 1:
return ['0', '1', '8']
result = []
for num in self.findStrobogrammaticRecu(n, k - 2):
for key, val in self.lookup.iteritems():
if n != k or key != '0':
result.append(key + num + val)
return result
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