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unique-paths-ii.py 676 Bytes
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Allen Liu 提交于 2018-10-13 13:24 +08:00 . update
# Time: O(m * n)
# Space: O(m + n)
class Solution(object):
# @param obstacleGrid, a list of lists of integers
# @return an integer
def uniquePathsWithObstacles(self, obstacleGrid):
"""
:type obstacleGrid: List[List[int]]
:rtype: int
"""
m, n = len(obstacleGrid), len(obstacleGrid[0])
ways = [0]*n
ways[0] = 1
for i in xrange(m):
if obstacleGrid[i][0] == 1:
ways[0] = 0
for j in xrange(n):
if obstacleGrid[i][j] == 1:
ways[j] = 0
elif j>0:
ways[j] += ways[j-1]
return ways[-1]
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