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unique-substrings-in-wraparound-string.py 562 Bytes
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Allen Liu 提交于 2018-10-12 01:33 +08:00 . remove sensitive question description
# Time: O(n)
# Space: O(1)
class Solution(object):
def findSubstringInWraproundString(self, p):
"""
:type p: str
:rtype: int
"""
letters = [0] * 26
result, length = 0, 0
for i in xrange(len(p)):
curr = ord(p[i]) - ord('a')
if i > 0 and ord(p[i-1]) != (curr-1)%26 + ord('a'):
length = 0
length += 1
if length > letters[curr]:
result += length - letters[curr]
letters[curr] = length
return result
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