代码拉取完成,页面将自动刷新
# Time: ctor: O(n), n is number of words in the dictionary.
# lookup: O(1)
# Space: O(k), k is number of unique words.
import collections
class ValidWordAbbr(object):
def __init__(self, dictionary):
"""
initialize your data structure here.
:type dictionary: List[str]
"""
self.lookup_ = collections.defaultdict(set)
for word in dictionary:
abbr = self.abbreviation(word)
self.lookup_[abbr].add(word)
def isUnique(self, word):
"""
check if a word is unique.
:type word: str
:rtype: bool
"""
abbr = self.abbreviation(word)
return self.lookup_[abbr] <= {word}
def abbreviation(self, word):
if len(word) <= 2:
return word
return word[0] + str(len(word)-2) + word[-1]
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。