Ai
1 Star 2 Fork 5

LilithSangreal/LeetCode-Solutions

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
克隆/下载
unique-word-abbreviation.py 851 Bytes
一键复制 编辑 原始数据 按行查看 历史
Allen Liu 提交于 2018-10-13 01:56 +08:00 . add complexity
# Time: ctor: O(n), n is number of words in the dictionary.
# lookup: O(1)
# Space: O(k), k is number of unique words.
import collections
class ValidWordAbbr(object):
def __init__(self, dictionary):
"""
initialize your data structure here.
:type dictionary: List[str]
"""
self.lookup_ = collections.defaultdict(set)
for word in dictionary:
abbr = self.abbreviation(word)
self.lookup_[abbr].add(word)
def isUnique(self, word):
"""
check if a word is unique.
:type word: str
:rtype: bool
"""
abbr = self.abbreviation(word)
return self.lookup_[abbr] <= {word}
def abbreviation(self, word):
if len(word) <= 2:
return word
return word[0] + str(len(word)-2) + word[-1]
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
1
https://gitee.com/LilithSangreal/LeetCode-Solutions.git
git@gitee.com:LilithSangreal/LeetCode-Solutions.git
LilithSangreal
LeetCode-Solutions
LeetCode-Solutions
master

搜索帮助