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16/data_structure_of_java

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Tree.java 3.84 KB
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16 提交于 2018-08-23 14:29 +08:00 . 上传一颗二叉搜索树
package Tree;
/**
* 二叉搜索树
* @author Administrator
*
*/
public class Tree {
public node root;
public Tree(int i,double f) {
this.root = new node(i,f);
}
/**
* 查找
* @param key
* @return
*/
public node find(int key) {
node current = this.root;
while(current.iData != key) {
if(key < current.iData) {
current = current.leftNode;
}else {
current = current.rightNode;
}
if(current == null) {
return null;
}
}
return current;
}
/**
* 插入数据
* @param i
* @param f
*/
public void insert(int i,double f) {
node newNode = new node(i,f);
if(this.root == null) {
this.root = newNode;
}else {
node current = this.root;
node parent;
while(true) {
parent = current;
if(i < current.iData) {
current = current.leftNode;
if(current == null) {
parent.leftNode = newNode;
return;
}
}else {
current = current.rightNode;
if(current == null) {
parent.rightNode = newNode;
return;
}
}
}
}
}
/**
* 中序遍历
* @param localRoot
*/
public void inOrder(node localRoot) {
if(localRoot != null) {
inOrder(localRoot.leftNode);
System.out.println(localRoot.iData);
inOrder(localRoot.rightNode);
}
}
/**
* 返回最小的值
* @return
*/
public node minimum() {
node current,last;
current = this.root;
last = null;
while(current != null) {
last = current;
current = current.leftNode;
}
return last;
}
/**
* 二叉搜索树的最大值
* @return
*/
public node maximun() {
node current,last;
current = this.root;
last = null;
while(current != null) {
last = current;
current = current.rightNode;
}
return last;
}
/**
* 删除拥有两个子节点的节点,要找到当前节点的中序后继节点,如果不是当前节点的右子节点那么还得反转下树
* @param delNode
* @return
*/
private node getSuccessor(node delNode) {
node successorParent = delNode;
node successor = delNode;
node current = delNode.rightNode;
while(current != null) {
successorParent = successor;
successor = current;
current = current.leftNode;
}
if(successor != delNode.rightNode) {
successorParent.leftNode = successor.rightNode;
successor.rightNode = delNode.rightNode;
}
return successor;
}
/**
* 删除一个节点
* @return
*/
public boolean delete(int key) {
node current = this.root;
node parent = this.root;
boolean isLeftChild = true;
//找到要删除的节点
while(current.iData != key) {
parent = current;
if(key < current.iData) {
isLeftChild = true;
current = current.leftNode;
}else {
isLeftChild = false;
current = current.rightNode;
}
if(current == null) {
return false;
}
}
//没有子节点的情况下
if(current.leftNode == null && current.rightNode == null) {
if(current == this.root) {
//根节点
this.root = null;
}else {
//叶子结点
if(isLeftChild) {
parent.leftNode = null;
}else {
parent.rightNode = null;
}
}
}else if(current.rightNode == null) {
//只有一个节点的情况下
if(current == this.root) {
//当前结点是根结点
this.root = this.root.leftNode;
}else if(isLeftChild) {
parent.leftNode = current.leftNode;
}else {
parent.rightNode = current.leftNode;
}
}else if(current.leftNode == null) {
//只有一个节点的情况下
if(current == this.root) {
//当前结点是根结点
this.root = this.root.rightNode;
}else if(isLeftChild) {
parent.leftNode = current.rightNode;
}else {
parent.rightNode = current.rightNode;
}
}else {
//两个子节点的情况下
node successor = this.getSuccessor(current);
if(current == this.root) {
root = successor;
}else if(isLeftChild) {
parent.leftNode = successor;
}else {
parent.rightNode = successor;
}
successor.leftNode = current.leftNode;
}
return true;
}
}
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