QT分布式计算框架
多线程水桶算法: 现有4个水桶，它们的容量为：21,11,8,5 水桶含有的水为：21 ,0 ,0 ,0 需要将水桶倒成：7,7,7,0 水桶之间可以互相倒水但不能溢出。 求需要的最小步骤为。 答案: 21 0 0 0 10 11 0 0 10 6 0 5 10 0 6 5 15 0 6 0 15 0 1 5 15 5 1 0 15 5 0 1 7 5 8 1 7 11 2 1 7 7 2 5 7 7 7 0
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