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_224_BasicCalculator.java 1.78 KB
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Cspiration authored 2019-01-31 06:56 +08:00 . Add files via upload
package leetcode_1To300;
import java.util.Stack;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _224_BasicCalculator {
/**
* 224. Basic Calculator
"1 + 1" = 2
" 2-1 + 2 " = 3
"(1+(4+5+2)-3)+(6+8)" = 23
time : O(n)
space : O(n)
* @param s
* @return
*/
public int calculate(String s) {
Stack<Integer> stack = new Stack<>();
int sign = 1;
int res = 0;
for (int i = 0; i < s.length(); i++) {
if (Character.isDigit(s.charAt(i))) {
int num = s.charAt(i) - '0';
while (i + 1 < s.length() && Character.isDigit(s.charAt(i + 1))) {
num = num * 10 + s.charAt(i + 1) - '0';
i++;
}
res += num * sign;
} else if (s.charAt(i) == '+') {
sign = 1;
} else if (s.charAt(i) == '-') {
sign = -1;
} else if (s.charAt(i) == '(') {
stack.push(res);
stack.push(sign);
res = 0;
sign = 1;
} else if (s.charAt(i) == ')') {
res = res * stack.pop() + stack.pop();
}
}
return res;
}
}
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