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_458_PoorPigs.java 1.76 KB
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Cspiration 提交于 2019-01-31 07:02 +08:00 . Add files via upload
package leetcode_301To600;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _458_PoorPigs {
/**
* There are 1000 buckets, one and only one of them contains poison,
* the rest are filled with water. They all look the same.
* If a pig drinks that poison it will die within 15 minutes.
* What is the minimum amount of pigs you need to figure out which bucket
* contains the poison within one hour.
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Answer this question, and write an algorithm for the follow-up general case.
Leetcode 326, 342
time : O(低) O(1)
space : O(1)
* @param buckets
* @param minutesToDie
* @param minutesToTest
* @return
*/
public int poorPigs(int buckets, int minutesToDie, int minutesToTest) {
int num = minutesToTest / minutesToDie + 1;
return (int)Math.ceil(Math.log(buckets) / Math.log(num));
}
public int poorPigs2(int buckets, int minutesToDie, int minutesToTest) {
int res = 0;
while (Math.pow(minutesToTest / minutesToDie + 1, res) < buckets) {
res += 1;
}
return res;
}
}
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