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_475_Heaters.java 2.72 KB
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Cspiration 提交于 2019-01-31 07:02 +08:00 . Add files via upload
package leetcode_301To600;
import java.util.Arrays;
import java.util.TreeSet;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _475_Heaters {
/**
* Example 1:
Input: [1,2,3],[2]
Output: 1
Explanation: The only heater was placed in the position 2, and if we use the radius 1 standard,
then all the houses can be warmed.
Example 2:
Input: [1,2,3,4],[1,4]
Output: 1
Explanation: The two heater was placed in the position 1 and 4. We need to use radius 1 standard,
then all the houses can be warmed.
time : O(nlogn)
space : O(1)
* @param houses
* @param heaters
* @return
*/
public int findRadius(int[] houses, int[] heaters) {
Arrays.sort(heaters);
Arrays.sort(houses);
int i = 0, res = 0;
for (int house : houses) {
while (i < heaters.length - 1
&& Math.abs(heaters[i + 1] - house) <= Math.abs(heaters[i] - house)) {
i++;
}
res = Math.max(res, Math.abs(heaters[i] - house));
}
return res;
}
public int findRadius2(int[] houses, int[] heaters) {
Arrays.sort(heaters);
int res = 0;
for (int house : houses) {
int index = Arrays.binarySearch(heaters, house);
if (index < 0) {
index = -(index + 1);
}
int dist1 = index - 1 >= 0 ? house - heaters[index - 1] : Integer.MAX_VALUE;
int dist2 = index < heaters.length ? heaters[index] - house : Integer.MAX_VALUE;
res = Math.max(res, Math.min(dist1, dist2));
}
return res;
}
public int findRadius3(int[] houses, int[] heaters) {
TreeSet<Integer> set = new TreeSet<>();
for (int heater : heaters) {
set.add(heater);
}
int index = 0, res = 0;
for (int house : houses) {
int dist1 = set.ceiling(house) == null ? Integer.MAX_VALUE : set.ceiling(house) - house;
int dist2 = set.floor(house) == null ? Integer.MAX_VALUE : house - set.floor(house);
res = Math.max(res, Math.min(dist1, dist2));
}
return res;
}
}
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