Ai
1 Star 0 Fork 0

idsutong/gqlgen

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
克隆/下载
context_field.go 2.02 KB
一键复制 编辑 原始数据 按行查看 历史
Adam 提交于 2020-02-17 07:27 +08:00 . bump to gqlparser v2
package graphql
import (
"context"
"time"
"github.com/vektah/gqlparser/v2/ast"
)
type key string
const resolverCtx key = "resolver_context"
// Deprecated: Use FieldContext instead
type ResolverContext = FieldContext
type FieldContext struct {
Parent *FieldContext
// The name of the type this field belongs to
Object string
// These are the args after processing, they can be mutated in middleware to change what the resolver will get.
Args map[string]interface{}
// The raw field
Field CollectedField
// The index of array in path.
Index *int
// The result object of resolver
Result interface{}
// IsMethod indicates if the resolver is a method
IsMethod bool
}
type FieldStats struct {
// When field execution started
Started time.Time
// When argument marshaling finished
ArgumentsCompleted time.Time
// When the field completed running all middleware. Not available inside field middleware!
Completed time.Time
}
func (r *FieldContext) Path() ast.Path {
var path ast.Path
for it := r; it != nil; it = it.Parent {
if it.Index != nil {
path = append(path, ast.PathIndex(*it.Index))
} else if it.Field.Field != nil {
path = append(path, ast.PathName(it.Field.Alias))
}
}
// because we are walking up the chain, all the elements are backwards, do an inplace flip.
for i := len(path)/2 - 1; i >= 0; i-- {
opp := len(path) - 1 - i
path[i], path[opp] = path[opp], path[i]
}
return path
}
// Deprecated: Use GetFieldContext instead
func GetResolverContext(ctx context.Context) *ResolverContext {
return GetFieldContext(ctx)
}
func GetFieldContext(ctx context.Context) *FieldContext {
if val, ok := ctx.Value(resolverCtx).(*FieldContext); ok {
return val
}
return nil
}
func WithFieldContext(ctx context.Context, rc *FieldContext) context.Context {
rc.Parent = GetFieldContext(ctx)
return context.WithValue(ctx, resolverCtx, rc)
}
func equalPath(a ast.Path, b ast.Path) bool {
if len(a) != len(b) {
return false
}
for i := 0; i < len(a); i++ {
if a[i] != b[i] {
return false
}
}
return true
}
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
1
https://gitee.com/idsutong/gqlgen.git
git@gitee.com:idsutong/gqlgen.git
idsutong
gqlgen
gqlgen
master

搜索帮助