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徐长贺/Leetcode

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_1079.java 1.71 KB
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Fisher Coder 提交于 6年前 . refactor 1079
package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.stream.IntStream;
/**
* 5087. Letter Tile Possibilities
*
* You have a set of tiles, where each tile has one letter tiles[i] printed on it.
* Return the number of possible non-empty sequences of letters you can make.
*
* Example 1:
* Input: "AAB"
* Output: 8
* Explanation: The possible sequences are "A", "B", "AA", "AB", "BA", "AAB", "ABA", "BAA".
*
* Example 2:
* Input: "AAABBC"
* Output: 188
*
* Note:
* 1. 1 <= tiles.length <= 7
* 2. tiles consists of uppercase English letters.
* */
public class _1079 {
public static class Solution1 {
public int numTilePossibilities(String tiles) {
char[] chars = tiles.toCharArray();
Arrays.sort(chars);
boolean[] used = new boolean[chars.length];
StringBuilder sb = new StringBuilder();
List<String> result = new ArrayList<>();
dfs(chars, used, sb, result);
return result.size();
}
private void dfs(char[] chars, boolean[] used, StringBuilder sb, List<String> result) {
if (sb.length() != 0) {
result.add(sb.toString());
}
IntStream.range(0, chars.length)
.filter(i -> !used[i])
.filter(i -> i <= 0 || chars[i - 1] != chars[i] || used[i - 1])
.forEach(i -> {
used[i] = true;
sb.append(chars[i]);
dfs(chars, used, sb, result);
used[i] = false;
sb.deleteCharAt(sb.length() - 1);
});
}
}
}
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