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徐长贺/Leetcode

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_186.java 1.15 KB
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Steve Sun 提交于 7年前 . refactor 186
package com.fishercoder.solutions;
/**
* 186. Reverse Words in a String II
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.
The input string does not contain leading or trailing spaces and the words are always separated by a single space.
For example,
Given s = "the sky is blue",
return "blue is sky the".
Could you do it in-place without allocating extra space?
*/
public class _186 {
public static class Solution1 {
public void reverseWords(char[] s) {
// Three steps to reverse
// 1, reverse the whole sentence
reverse(s, 0, s.length - 1);
// 2, reverse each word
int start = 0;
for (int i = 0; i < s.length; i++) {
if (s[i] == ' ') {
reverse(s, start, i - 1);
start = i + 1;
}
}
// 3, reverse the last word, if there is only one word this will solve the corner case
reverse(s, start, s.length - 1);
}
private void reverse(char[] s, int start, int end) {
while (start < end) {
char temp = s[start];
s[start++] = s[end];
s[end--] = temp;
}
}
}
}
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