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徐长贺/Leetcode

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_20.java 2.37 KB
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package com.fishercoder.solutions;
import java.util.Stack;
/**
* 20. Valid Parentheses
*
* Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
*
* An input string is valid if:
*
* 1. Open brackets must be closed by the same type of brackets.
* 2. Open brackets must be closed in the correct order.
*
* Note that an empty string is also considered valid.
*
* Example 1:
* Input: "()"
* Output: true
*
* Example 2:
* Input: "()[]{}"
* Output: true
*
* Example 3:
* Input: "(]"
* Output: false
*
* Example 4:
* Input: "([)]"
* Output: false
*
* Example 5:
* Input: "{[]}"
* Output: true
* */
public class _20 {
public static class Solution1 {
public boolean isValid(String s) {
Stack<Character> stack = new Stack<>();
for (int i = 0; i < s.length(); i++) {
if (s.charAt(i) == '(' || s.charAt(i) == '{' || s.charAt(i) == '[') {
stack.push(s.charAt(i));
} else {
if (stack.isEmpty()) {
return false;
} else {
if (stack.peek() == '(' && s.charAt(i) != ')') {
return false;
} else if (stack.peek() == '{' && s.charAt(i) != '}') {
return false;
} else if (stack.peek() == '[' && s.charAt(i) != ']') {
return false;
}
stack.pop();
}
}
}
return stack.isEmpty();
}
}
public static class Solution2 {
/**
* A more concise solution:
* credit: https://leetcode.com/problems/valid-parentheses/discuss/9178/Short-java-solution
* */
public boolean isValid(String s) {
Stack<Character> stack = new Stack<>();
for (char c : s.toCharArray()) {
if (c == '(') {
stack.push(')');
} else if (c == '{') {
stack.push('}');
} else if (c == '[') {
stack.push(']');
} else if (stack.isEmpty() || stack.pop() != c) {
return false;
}
}
return stack.isEmpty();
}
}
}
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