package com.fishercoder.solutions;

/**
 * 211. Add and Search Word - Data structure design
 *
 * Design a data structure that supports the following two operations:

 void addWord(word)
 bool search(word)
 search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter.

 For example:

 addWord("bad")
 addWord("dad")
 addWord("mad")
 search("pad") -> false
 search("bad") -> true
 search(".ad") -> true
 search("b..") -> true
 Note:
 You may assume that all words are consist of lowercase letters a-z.

 You should be familiar with how a Trie works. If not, please work on this problem: Implement Trie (Prefix Tree) first.
 */
public class _211 {
  public static class Solution1 {
    public static class WordDictionary {
      WordNode root;

      /** Initialize your data structure here. */
      public WordDictionary() {
        root = new WordNode();
      }

      public void addWord(String word) {
        char[] chars = word.toCharArray();
        addWord(chars, 0, root);
      }

      private void addWord(char[] chars, int index, WordNode parent) {
        char c = chars[index];
        int idx = c - 'a';
        WordNode node = parent.children[idx];
        if (node == null) {
          node = new WordNode();
          parent.children[idx] = node;
        }
        if (chars.length == index + 1) {
          node.isLeaf = true;
          return;
        }
        addWord(chars, ++index, node);
      }

      public boolean search(String word) {
        return search(word.toCharArray(), 0, root);
      }

      /** This is also a beautifully designed recursive function. */
      private boolean search(char[] chars, int index, WordNode parent) {
        if (index == chars.length) {
          if (parent.isLeaf) {
            return true;
          }
          return false;
        }
        WordNode[] childNodes = parent.children;
        char c = chars[index];
        if (c == '.') {
          for (int i = 0; i < childNodes.length; i++) {
            WordNode n = childNodes[i];
            if (n != null) {
              boolean b = search(chars, index + 1, n);
              if (b) {
                return true;
              }
            }
          }
          return false;
        }
        WordNode node = childNodes[c - 'a'];
        if (node == null) {
          return false;
        }
        return search(chars, ++index, node);
      }

      /** This is a cool/standard design for a Trie node class. */
      private class WordNode {
        boolean isLeaf;
        WordNode[] children = new WordNode[26];
      }
    }

    /**
     * Your WordDictionary object will be instantiated and called as such:
     * WordDictionary obj = new WordDictionary();
     * obj.addWord(word);
     * boolean param_2 = obj.search(word);
     */
  }
}