package com.fishercoder.solutions;

/**
 214. Shortest Palindrome

 Given a string S, you are allowed to convert it to a palindrome
 by adding characters in front of it.
 Find and return the shortest palindrome you can find by performing this transformation.

 For example:

 Given "aacecaaa", return "aaacecaaa".

 Given "abcd", return "dcbabcd".
 */
public class _214 {

    public static class Solution1 {
        /**credit: https://discuss.leetcode.com/topic/27261/clean-kmp-solution-with-super-detailed-explanation*/
        /**
         * TODO: read it explanation and understand KMP completely.
         */
        public String shortestPalindrome(String s) {
            String temp = s + "#" + new StringBuilder(s).reverse().toString();
            int[] table = getTable(temp);
            //get the maximum palin part in s starts from 0
            return new StringBuilder(s.substring(table[table.length - 1])).reverse().toString() + s;
        }

        public int[] getTable(String s) {
            //get lookup table
            int[] table = new int[s.length()];

            //pointer that points to matched char in prefix part
            int index = 0;
            //skip index 0, we will not match a string with itself
            for (int i = 1; i < s.length(); i++) {
                if (s.charAt(index) == s.charAt(i)) {
                    //we can extend match in prefix and postfix
                    table[i] = table[i - 1] + 1;
                    index++;
                } else {
                    //match failed, we try to match a shorter substring

                    //by assigning index to table[i-1], we will shorten the match string length, and jump to the
                    //prefix part that we used to match postfix ended at i - 1
                    index = table[i - 1];

                    while (index > 0 && s.charAt(index) != s.charAt(i)) {
                        //we will try to shorten the match string length until we revert to the beginning of match (index 1)
                        index = table[index - 1];
                    }

                    //when we are here may either found a match char or we reach the boundary and still no luck
                    //so we need check char match
                    if (s.charAt(index) == s.charAt(i)) {
                        //if match, then extend one char
                        index++;
                    }
                    table[i] = index;
                }
            }
            return table;
        }
    }
}