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徐长贺/Leetcode

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_33.java 2.56 KB
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stevesun 提交于 8年前 . [N-0] fix build
package com.fishercoder.solutions;
/**
* 33. Search in Rotated Sorted Array
*
* Suppose a sorted array is rotated at some pivot unknown to you beforehand.
* (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
* You are given a target value to search. If found in the array return its index, otherwise return -1.
* You may assume no duplicate exists in the array.
*/
public class _33 {
public static class Solution1 {
public int search(int[] nums, int target) {
if (nums == null || nums.length == 0) {
return -1;
}
int minIdx = findMinIdx(nums);
if (target == nums[minIdx]) {
return minIdx;
}
int m = nums.length;
int start = (target <= nums[m - 1]) ? minIdx : 0;
int end = (target > nums[m - 1]) ? minIdx : m - 1;
while (start <= end) {
int mid = start + (end - start) / 2;
if (nums[mid] == target) {
return mid;
} else if (target > nums[mid]) {
start = mid + 1;
} else {
end = mid - 1;
}
}
return -1;
}
private int findMinIdx(int[] nums) {
int start = 0;
int end = nums.length - 1;
while (start < end) {
int mid = start + (end - start) / 2;
if (nums[mid] > nums[end]) {
start = mid + 1;
} else {
end = mid;
}
}
return start;
}
}
public static class Solution2 {
public int search(int[] nums, int target) {
if (nums == null || nums.length == 0) {
return -1;
}
int lo = 0;
int hi = nums.length - 1;
while (lo < hi) {
int mid = (lo + hi) / 2;
if (nums[mid] == target) {
return mid;
}
if (nums[lo] <= nums[mid]) {
if (target >= nums[lo] && target < nums[mid]) {
hi = mid - 1;
} else {
lo = mid + 1;
}
} else {
if (target > nums[mid] && target <= nums[hi]) {
lo = mid + 1;
} else {
hi = mid - 1;
}
}
}
return nums[lo] == target ? lo : -1;
}
}
}
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