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徐长贺/Leetcode

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_336.java 2.05 KB
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Fisher Coder 提交于 2019-01-08 23:14 +08:00 . refactor 336
package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
/**336. Palindrome Pairs
*
* Given a list of unique words, find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome.
Example 1:
Given words = ["bat", "tab", "cat"]
Return [[0, 1], [1, 0]]
The palindromes are ["battab", "tabbat"]
Example 2:
Given words = ["abcd", "dcba", "lls", "s", "sssll"]
Return [[0, 1], [1, 0], [3, 2], [2, 4]]
The palindromes are ["dcbaabcd", "abcddcba", "slls", "llssssll"]
*/
public class _336 {
public static class Solution1 {
public List<List<Integer>> palindromePairs(String[] words) {
List<List<Integer>> pairs = new ArrayList();
Map<String, Integer> map = new HashMap();
for (int i = 0; i < words.length; i++) {
map.put(words[i], i);
}
for (int i = 0; i < words.length; i++) {
int l = 0;
int r = 0;
while (l <= r) {
String s = words[i].substring(l, r);
Integer j = map.get(new StringBuilder(s).reverse().toString());
if (j != null && j != i && isPalindrome(
words[i].substring(l == 0 ? r : 0, l == 0 ? words[i].length() : l))) {
pairs.add(
Arrays.asList(l == 0 ? new Integer[] {i, j} : new Integer[] {j, i}));
}
if (r < words[i].length()) {
r++;
} else {
l++;
}
}
}
return pairs;
}
private boolean isPalindrome(String s) {
for (int i = 0; i < s.length() / 2; i++) {
if (s.charAt(i) != s.charAt(s.length() - 1 - i)) {
return false;
}
}
return true;
}
}
}
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