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_48.java 4.03 KB
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Fisher Coder 提交于 2020-01-11 00:13 +08:00 . refactor 48
package com.fishercoder.solutions;
import com.fishercoder.common.utils.CommonUtils;
/**
* 48. Rotate Image
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the
input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix =
[
[1,2,3],
[4,5,6],
[7,8,9]
],
rotate the input matrix in-place such that it becomes:
[
[7,4,1],
[8,5,2],
[9,6,3]
]
Example 2:
Given input matrix =
[
[ 5, 1, 9,11],
[ 2, 4, 8,10],
[13, 3, 6, 7],
[15,14,12,16]
],
rotate the input matrix in-place such that it becomes:
[
[15,13, 2, 5],
[14, 3, 4, 1],
[12, 6, 8, 9],
[16, 7,10,11]
]
*/
public class _48 {
/**Note: this is an n*n matrix, in other words, it's a square, this makes it easier as well.*/
public static class Solution1 {
//Time: O(n^2)
//Space: O(1)
public void rotate(int[][] matrix) {
/**First swap the elements on the diagonal, then reverse each row:
* 1, 2, 3 1, 4, 7 7, 4, 1
* 4, 5, 6 becomes 2, 5, 8 becomes 8, 5, 2
* 7, 8, 9 3, 6, 9 9, 6, 3
**/
int m = matrix.length;
for (int i = 0; i < m; i++) {
for (int j = i; j < m; j++) {
/**ATTN: j starts from i, so that the diagonal changes with itself, results in no change.*/
int tmp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = tmp;
}
}
CommonUtils.print2DIntArray(matrix);
/**then reverse*/
for (int i = 0; i < m; i++) {
int left = 0;
int right = m - 1;
while (left < right) {
int tmp = matrix[i][left];
matrix[i][left] = matrix[i][right];
matrix[i][right] = tmp;
left++;
right--;
}
}
}
}
public static class Solution2 {
/**First swap the rows bottom up, then swap the element on the diagonal:
*
* 1, 2, 3 7, 8, 9 7, 4, 1
* 4, 5, 6 becomes 4, 5, 6 becomes 8, 5, 2
* 7, 8, 9 1, 2, 3 9, 6, 3
*
* Time: O(n^2)
* Space: O(1)
*/
public void rotate(int[][] matrix) {
int m = matrix.length;
int n = matrix[0].length;
int top = 0;
int bottom = n - 1;
while (top < bottom) {
int[] tmp = matrix[top];
matrix[top] = matrix[bottom];
matrix[bottom] = tmp;
top++;
bottom--;
}
for (int i = 0; i < m; i++) {
for (int j = i + 1; j < n; j++) {
int tmp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = tmp;
}
}
}
}
public static class Solution3 {
public void rotate(int[][] matrix) {
int n = matrix.length;
for (int i = 0; i < n / 2; i++) {
for (int j = i; j < n - i - 1; j++) {
//save the top
int top = matrix[i][j];
//move left to top
matrix[i][j] = matrix[n - 1 - j][i];
//move bottom to left
matrix[n - 1 - j][i] = matrix[n - i - 1][n - 1 - j];
//move right to bottom
matrix[n - i - 1][n - 1 - j] = matrix[j][n - i - 1];
//move top to right
matrix[j][n - i - 1] = top;
}
}
}
}
}
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